anonymous
  • anonymous
Simplify this expression
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[ \huge \ln e^{\sin^2x} + \ln e^{\cos^2x} \]
anonymous
  • anonymous
hah., a
anonymous
  • anonymous
the answer is one.. but how ?!

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More answers

anonymous
  • anonymous
its a nice problem
anonymous
  • anonymous
its 0
anonymous
  • anonymous
no my answerkey says 1
anonymous
  • anonymous
:'( walks in shame
anonymous
  • anonymous
\[\cos^2x \ln e+\sin^2x \ln e\] but \[\ln e\] is 1
anonymous
  • anonymous
since \[\ln e = \log_{e} ^e\]
anonymous
  • anonymous
\[\sin^2x+\cos^2x\]
anonymous
  • anonymous
we know that \[\cos^2x+\sin^2x=1\] in trigonometry
anonymous
  • anonymous
thast why the answer is one
anonymous
  • anonymous
log e is = to lin
anonymous
  • anonymous
thank you :D
anonymous
  • anonymous
so log e to e to 1 is 1
anonymous
  • anonymous
you're welcome..

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