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finalaeon123
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The volume. V cm^3, of a cone of height h is (pi)h^3/12. If h increases at a constant rate of 0.2cm/s and the initial height is 2cm, express V in interms of t and find the rate of change of V at time t.
 one year ago
 one year ago
finalaeon123 Group Title
The volume. V cm^3, of a cone of height h is (pi)h^3/12. If h increases at a constant rate of 0.2cm/s and the initial height is 2cm, express V in interms of t and find the rate of change of V at time t.
 one year ago
 one year ago

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myininaya Group TitleBest ResponseYou've already chosen the best response.1
So we have \[V(x)=\frac{\pi }{12} (h(x))^3\] We will let x represent the variable time for now.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Find derivative of both sides.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
With respect to x
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Both V and h are functions of time this implies that both V and h are functions of x
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
So derivative of V is V' and derivative of h is h'
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
So tell me what does V' equal?
 one year ago
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