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anonymous
 2 years ago
Determine the extreme values of this function on the given interval.
f(x)= 1+ (x+3)² ; 2<x<6
anonymous
 2 years ago
Determine the extreme values of this function on the given interval. f(x)= 1+ (x+3)² ; 2<x<6

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0precal @SithsAndGiggles

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Ok, that method's a bit less work. So you're given a parabola in vertex form: \[f(x)=1+(x+3)^2\] \(f(x)\) has vertex (an extreme value point) at \((3,1)\). \(3\) is not in the interval \(2<x<6\). So, you have something that looks like this: dw:1371696732887:dw This means that only the endpoints of this interval will contain the extreme values.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Which means you have only to check \(f(2)\) and \(f(6)\).

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0where did you get (3,1) from ? :S
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