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burhan101
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Determine the extreme values of this function on the given interval.
f(x)= 1+ (x+3)² ; 2<x<6
 one year ago
 one year ago
burhan101 Group Title
Determine the extreme values of this function on the given interval. f(x)= 1+ (x+3)² ; 2<x<6
 one year ago
 one year ago

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SithsAndGiggles Group TitleBest ResponseYou've already chosen the best response.0
Calc or precalc?
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
precal @SithsAndGiggles
 one year ago

SithsAndGiggles Group TitleBest ResponseYou've already chosen the best response.0
Ok, that method's a bit less work. So you're given a parabola in vertex form: \[f(x)=1+(x+3)^2\] \(f(x)\) has vertex (an extreme value point) at \((3,1)\). \(3\) is not in the interval \(2<x<6\). So, you have something that looks like this: dw:1371696732887:dw This means that only the endpoints of this interval will contain the extreme values.
 one year ago

SithsAndGiggles Group TitleBest ResponseYou've already chosen the best response.0
Which means you have only to check \(f(2)\) and \(f(6)\).
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
where did you get (3,1) from ? :S
 one year ago
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