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burhan101
 one year ago
Determine the extreme values of this function on the given interval.
f(x)= 1+ (x+3)² ; 2<x<6
burhan101
 one year ago
Determine the extreme values of this function on the given interval. f(x)= 1+ (x+3)² ; 2<x<6

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SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.0Calc or precalc?

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0precal @SithsAndGiggles

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.0Ok, that method's a bit less work. So you're given a parabola in vertex form: \[f(x)=1+(x+3)^2\] \(f(x)\) has vertex (an extreme value point) at \((3,1)\). \(3\) is not in the interval \(2<x<6\). So, you have something that looks like this: dw:1371696732887:dw This means that only the endpoints of this interval will contain the extreme values.

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.0Which means you have only to check \(f(2)\) and \(f(6)\).

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0where did you get (3,1) from ? :S
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