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Evaluate the line integral 5ydx+2xdy where C is the straight line path from (4,4) to (7,8)

Mathematics
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I got 276 but was wrong
@Hero please help!
\[\int_C (5y~dx+2x~dy)\] The line connecting (4,4) and (7,8) is \(y=\dfrac{4}{3}x-\dfrac{4}{3}\) Parameterize \(C\) by \[\begin{cases}x=t\\ \\ y=\dfrac{4}{3}t-\dfrac{4}{3}\\ \\ 4

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Other answers:

did you get 134?
Yep: http://www.wolframalpha.com/input/?i=Integrate%5B%2828%2F3%29*t-%2820%2F3%29%2C%7Bt%2C4%2C7%7D%5D Can't guarantee that's the right answer, but that's what my method is getting, so I'm sticking with it.
when i did it by hand, i ended up getting 288
Could you show your work? It might be a mistake in the integration, or the parameterization.
288 is wrong :(
Well what did you do when you tried it? How did you parameterize \(C\)?
no i integrated wrong! the answer is indeed 134
Oh ok then.
Thanks so much
You're welcome!

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