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anonymous
 2 years ago
Solve for 'x'
anonymous
 2 years ago
Solve for 'x'

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[\huge 0=1 \frac{ 1 }{ 2x^{\frac{ 3 }{ 2}}} \]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1371705222820:dw

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0how does it equal one ?!

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.2slowly :D Why don't we bring \(\huge \frac1{2x^{\frac32}}\) to the left side like this... \[\Large \frac1{2x^{\frac32}}=1\] clear now? :)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1371743475441:dw

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.2We basically added \[\huge \frac1{2x^{\frac32}}\] to both sides as per the addition property of equality.

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.2Well then, can you solve it from here?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0do i multiply by both sides?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1371743682268:dw

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.2Never mind that for now. Why don't we multiply both sides by \[\Large 2x^{\frac32}\] That gives us... \[\Large 1 = 2x^{\frac32}\] And divide both sides by 2...

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.2true dat :) Now you can raise both sides to the \(\LARGE \frac23\) power (just to get rid of the exponent of x) You then get...?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1371743929750:dw like this?

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.2That gives you x. What about the righthand side?

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.2Oh, were you supposed to give it in decimal form? okay then :D

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I can get a fraction answer too?

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.2Well, the best you can hope for is the uglylooking \[\Large \left(\frac12\right)^{\frac23}\]

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.2and that is the correct answer :)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0oh so i should probably keep it,

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.2Yeah, unless you were specifically asked for an approximation :)

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.2Oh well... now I have to go :) Please practice solving algebraic equations :D  Terence out
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