anonymous
  • anonymous
Solve for 'x'
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[\huge 0=1- \frac{ 1 }{ 2x^{\frac{ 3 }{ 2}}} \]
anonymous
  • anonymous
|dw:1371705222820:dw|
anonymous
  • anonymous
how does it equal one ?!

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More answers

terenzreignz
  • terenzreignz
slowly :D Why don't we bring \(\huge \frac1{2x^{\frac32}}\) to the left side like this... \[\Large \frac1{2x^{\frac32}}=1\] clear now? :)
anonymous
  • anonymous
|dw:1371743475441:dw|
anonymous
  • anonymous
yes
terenzreignz
  • terenzreignz
We basically added \[\huge \frac1{2x^{\frac32}}\] to both sides as per the addition property of equality.
terenzreignz
  • terenzreignz
Well then, can you solve it from here?
anonymous
  • anonymous
do i multiply by both sides?
terenzreignz
  • terenzreignz
Sure :)
anonymous
  • anonymous
|dw:1371743682268:dw|
terenzreignz
  • terenzreignz
Never mind that for now. Why don't we multiply both sides by \[\Large 2x^{\frac32}\] That gives us... \[\Large 1 = 2x^{\frac32}\] And divide both sides by 2...
anonymous
  • anonymous
\[x^{3/2} =1/2 \]
terenzreignz
  • terenzreignz
true dat :) Now you can raise both sides to the \(\LARGE \frac23\) power (just to get rid of the exponent of x) You then get...?
anonymous
  • anonymous
|dw:1371743929750:dw| like this?
terenzreignz
  • terenzreignz
That gives you x. What about the right-hand side?
anonymous
  • anonymous
0/63
anonymous
  • anonymous
0.63 *
terenzreignz
  • terenzreignz
come again? :D
terenzreignz
  • terenzreignz
Oh, were you supposed to give it in decimal form? okay then :D
anonymous
  • anonymous
I can get a fraction answer too?
terenzreignz
  • terenzreignz
Well, the best you can hope for is the ugly-looking \[\Large \left(\frac12\right)^{\frac23}\]
terenzreignz
  • terenzreignz
and that is the correct answer :)
anonymous
  • anonymous
oh so i should probably keep it,
anonymous
  • anonymous
thank youuu !!!
terenzreignz
  • terenzreignz
Yeah, unless you were specifically asked for an approximation :)
terenzreignz
  • terenzreignz
Oh well... now I have to go :) Please practice solving algebraic equations :D ----------------------------------------- Terence out

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