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\[\huge 0=1- \frac{ 1 }{ 2x^{\frac{ 3 }{ 2}}} \]
|dw:1371705222820:dw|
how does it equal one ?!

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Other answers:

slowly :D Why don't we bring \(\huge \frac1{2x^{\frac32}}\) to the left side like this... \[\Large \frac1{2x^{\frac32}}=1\] clear now? :)
|dw:1371743475441:dw|
yes
We basically added \[\huge \frac1{2x^{\frac32}}\] to both sides as per the addition property of equality.
Well then, can you solve it from here?
do i multiply by both sides?
Sure :)
|dw:1371743682268:dw|
Never mind that for now. Why don't we multiply both sides by \[\Large 2x^{\frac32}\] That gives us... \[\Large 1 = 2x^{\frac32}\] And divide both sides by 2...
\[x^{3/2} =1/2 \]
true dat :) Now you can raise both sides to the \(\LARGE \frac23\) power (just to get rid of the exponent of x) You then get...?
|dw:1371743929750:dw| like this?
That gives you x. What about the right-hand side?
0/63
0.63 *
come again? :D
Oh, were you supposed to give it in decimal form? okay then :D
I can get a fraction answer too?
Well, the best you can hope for is the ugly-looking \[\Large \left(\frac12\right)^{\frac23}\]
and that is the correct answer :)
oh so i should probably keep it,
thank youuu !!!
Yeah, unless you were specifically asked for an approximation :)
Oh well... now I have to go :) Please practice solving algebraic equations :D ----------------------------------------- Terence out

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