Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
avshvk
Group Title
f(x) = e^(1/x) / (1+ e^(1/x)) except x=0
and 0 if x=0
find whether f(x) is continuous
 one year ago
 one year ago
avshvk Group Title
f(x) = e^(1/x) / (1+ e^(1/x)) except x=0 and 0 if x=0 find whether f(x) is continuous
 one year ago
 one year ago

This Question is Closed

avshvk Group TitleBest ResponseYou've already chosen the best response.0
\[f(x) = \frac{e^{1/x}}{ 1+ e^{1/x} }, if x \neq 0\]
 one year ago

Abhishek619 Group TitleBest ResponseYou've already chosen the best response.0
check if the right and the left limit exists and are defined, and if the limits are equal tot he functional value at x=0, then it is continuous at x=0.
 one year ago

Abhishek619 Group TitleBest ResponseYou've already chosen the best response.0
does the left limit exists?
 one year ago

avshvk Group TitleBest ResponseYou've already chosen the best response.0
no idea if we apply limit for e^(1/x) then it will be e^infinity which is equal to inifinity but f(0)=0. Therefore f(0) neq to limit, hence it is discontinuous at x=0. Not sure whether my solution is correct or not??
 one year ago

Abhishek619 Group TitleBest ResponseYou've already chosen the best response.0
left limit=0, right limit=1 hence both the limits exists, but are not equal. If at all there exists a functional value, it is of no use, because left limit is not equal to right limit to check the continuity of the function. hence, the function is discontinuous at x=0.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.