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\[\huge y= \frac{ e^{x} }{ 1+e^{x} }, x \epsilon [0,4]\]

values maximum, minimum

yes, how tho?

i find the derivative first and then what?

first fint derivative that gives the result y'=ex/(1+ex)2 then eqaute it to zero gives ex=0

\[\huge y'=\frac{ e^x }{ (1+e^x) }\]

check if the function is increasing or decreasing?

Here's a graph to show you that it is always increasing

how do i check if its inc/dec?

Do you see that fozia's derivative is correct? That's where you should start.

Use the quotient rule to get the derivative. Do you need help with that?

@burhan101 I have 2 pending questions posted for you here.

@tcarroll010 im trying to figure out how that derivative is right

& yes i am using the quotient rule

\[\huge \frac{ (1+e^x)(e^x)-(e^x)(e^x)}{ (1+e^x)^2 }\]

ohhhh is see it

but dont i plug in 0 and 4 in f(x) ?

So, min at:
e^0 / (1 + e^0)
max at:
e^4 / (1 + e^4)

All good now, @burhan101 ?

yes thanks !!

uw! Good luck in all of your studies and thx for the recognition! @burhan101

thank you very much, you do explain things very clear !

I just like to help. Kind words on your part!

YO BURHAANN MY BRO

are u done with this equation

dannn:) ! no im not, do i plug the endpoints into the function ?

explain the meaning of an extreme value to me

an absolute mx or an absolute min

ok

so that means the slope there is 0

yes

but u must check the end points too incase its just a local max or local min there

first solve
f'(x) = 0

|dw:1371749721969:dw|

so i solve for x

yes

okay lemme give u some simpler exmaples

|dw:1371749857123:dw|

what are the extreme values for a parabola

the vertex

okay and the slope there is?

so that means the derivative there is?

|dw:1371749935529:dw|

what nooo

ohh:(

0/8 = 0|dw:1371749995868:dw|

0=cos4x?

@bahrom7893 http://multiplayerchess.com/#!/5gqIqmm

hello bahrom jhanny wants us to play a game

what's the next step ..

1what values of x wud make cos4x=0 think about cos pi/2=0 so what much it be

must*

ill give u one of the values that is in between 0 and pi
cos(4(pi/8)) = 0 thats one

okay

would i keep my calculator in degrees or radians?

|dw:1371751462417:dw|

i told him to look at those points too :) but its not really needed in this case