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iamsammybear
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Consider f(x)=sin^2(x)cos(x) on the interval 0 is less than or equal to x which is less than or equal to pi.
Determine the local extrema of f(x).
 one year ago
 one year ago
iamsammybear Group Title
Consider f(x)=sin^2(x)cos(x) on the interval 0 is less than or equal to x which is less than or equal to pi. Determine the local extrema of f(x).
 one year ago
 one year ago

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iamsammybear Group TitleBest ResponseYou've already chosen the best response.0
\[f(\theta)=\sin^{2}(\theta)\cos(\theta)\] \[0\le \theta \le \pi\]
 one year ago

iamsammybear Group TitleBest ResponseYou've already chosen the best response.0
I know one of the local extrema is at x=0. There are two more.
 one year ago

niksva Group TitleBest ResponseYou've already chosen the best response.1
in order to find the local extrema first differentiate f(x) with respect to x and then put f '(x) = 0 this will help u in getting local extrema
 one year ago

iamsammybear Group TitleBest ResponseYou've already chosen the best response.0
I get:\[\sin(\theta)(2\cos(\theta)+1)=0\]
 one year ago

iamsammybear Group TitleBest ResponseYou've already chosen the best response.0
I know the sin (theta) piece is what give the local extrema at x=0. But I can't figure out the cos part.
 one year ago

niksva Group TitleBest ResponseYou've already chosen the best response.1
ok 2{cos (theta) + 1} = 0 now can we write cos(theta) + 1 = 0?
 one year ago

niksva Group TitleBest ResponseYou've already chosen the best response.1
cos(theta) = 1 cos(theta) = cos(n* pi) where n is an odd integer is this step clear to u ?
 one year ago

niksva Group TitleBest ResponseYou've already chosen the best response.1
i m sorry its wrong
 one year ago

iamsammybear Group TitleBest ResponseYou've already chosen the best response.0
Yes, I am trying to find the angle that gives the odd integer?
 one year ago

niksva Group TitleBest ResponseYou've already chosen the best response.1
let me correct its 2cos(theta) +1 = 0 2cos(theta) = 1 cos(theta) = 1/2 is this step clear to u?
 one year ago

niksva Group TitleBest ResponseYou've already chosen the best response.1
as we know cosine function is negative in second and third quadrant therefore , value of theta must lie in pi/2 < theta < 3*pi/2
 one year ago

iamsammybear Group TitleBest ResponseYou've already chosen the best response.0
2pi/3 or 4 pi/3
 one year ago

iamsammybear Group TitleBest ResponseYou've already chosen the best response.0
Do I then restrict those answers based on the domain?
 one year ago

iamsammybear Group TitleBest ResponseYou've already chosen the best response.0
So then 2pi/3 is the only one that works?
 one year ago
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