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anonymous
 3 years ago
Consider f(x)=sin^2(x)cos(x) on the interval 0 is less than or equal to x which is less than or equal to pi.
Determine the local extrema of f(x).
anonymous
 3 years ago
Consider f(x)=sin^2(x)cos(x) on the interval 0 is less than or equal to x which is less than or equal to pi. Determine the local extrema of f(x).

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[f(\theta)=\sin^{2}(\theta)\cos(\theta)\] \[0\le \theta \le \pi\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I know one of the local extrema is at x=0. There are two more.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0in order to find the local extrema first differentiate f(x) with respect to x and then put f '(x) = 0 this will help u in getting local extrema

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I get:\[\sin(\theta)(2\cos(\theta)+1)=0\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I know the sin (theta) piece is what give the local extrema at x=0. But I can't figure out the cos part.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok 2{cos (theta) + 1} = 0 now can we write cos(theta) + 1 = 0?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cos(theta) = 1 cos(theta) = cos(n* pi) where n is an odd integer is this step clear to u ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, I am trying to find the angle that gives the odd integer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let me correct its 2cos(theta) +1 = 0 2cos(theta) = 1 cos(theta) = 1/2 is this step clear to u?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0as we know cosine function is negative in second and third quadrant therefore , value of theta must lie in pi/2 < theta < 3*pi/2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do I then restrict those answers based on the domain?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So then 2pi/3 is the only one that works?
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