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kjuchiha

Please help: Find all solutions to the equation. sin^2(x) + sin (x) = 0

  • 10 months ago
  • 10 months ago

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  1. mukushla
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    ok u know that\[\sin 2x=2 \sin x\cos x\]so equation becomes\[2 \sin x\cos x+\sin x=0\]take out common factor\[\sin x(2\cos x+1)=0\]using zero product property\[\sin x=0\]or\[2\cos x+1=0\]

    • 10 months ago
  2. kjuchiha
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    but the equation is sin^2(x)

    • 10 months ago
  3. mukushla
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    oh sorry\[\sin^2 x+\sin x=0\]take out common factor\[\sin x(\sin x+1)=0\]easier :)

    • 10 months ago
  4. mukushla
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    \[\sin x=0\]or\[\sin x=-1\]

    • 10 months ago
  5. mukushla
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    makes sense?

    • 10 months ago
  6. kjuchiha
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    a little but i dont know how to get the solutions

    • 10 months ago
  7. Supenova
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    u start like this: Let x be sin(x) and x^2+x=0 x(x+1)=0 then, x=0; & x=-1 sin is at radian -3/4pi and pi

    • 10 months ago
  8. Supenova
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    u substitute x value in sin(x) and -1 is co-terminal (270) angle and 0

    • 10 months ago
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