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mukushla
 one year ago
Best ResponseYou've already chosen the best response.0ok u know that\[\sin 2x=2 \sin x\cos x\]so equation becomes\[2 \sin x\cos x+\sin x=0\]take out common factor\[\sin x(2\cos x+1)=0\]using zero product property\[\sin x=0\]or\[2\cos x+1=0\]

kjuchiha
 one year ago
Best ResponseYou've already chosen the best response.0but the equation is sin^2(x)

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0oh sorry\[\sin^2 x+\sin x=0\]take out common factor\[\sin x(\sin x+1)=0\]easier :)

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0\[\sin x=0\]or\[\sin x=1\]

kjuchiha
 one year ago
Best ResponseYou've already chosen the best response.0a little but i dont know how to get the solutions

Supenova
 one year ago
Best ResponseYou've already chosen the best response.0u start like this: Let x be sin(x) and x^2+x=0 x(x+1)=0 then, x=0; & x=1 sin is at radian 3/4pi and pi

Supenova
 one year ago
Best ResponseYou've already chosen the best response.0u substitute x value in sin(x) and 1 is coterminal (270) angle and 0
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