anonymous
  • anonymous
Please help: Find all solutions to the equation. sin^2(x) + sin (x) = 0
Precalculus
katieb
  • katieb
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anonymous
  • anonymous
ok u know that\[\sin 2x=2 \sin x\cos x\]so equation becomes\[2 \sin x\cos x+\sin x=0\]take out common factor\[\sin x(2\cos x+1)=0\]using zero product property\[\sin x=0\]or\[2\cos x+1=0\]
anonymous
  • anonymous
but the equation is sin^2(x)
anonymous
  • anonymous
oh sorry\[\sin^2 x+\sin x=0\]take out common factor\[\sin x(\sin x+1)=0\]easier :)

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anonymous
  • anonymous
\[\sin x=0\]or\[\sin x=-1\]
anonymous
  • anonymous
makes sense?
anonymous
  • anonymous
a little but i dont know how to get the solutions
anonymous
  • anonymous
u start like this: Let x be sin(x) and x^2+x=0 x(x+1)=0 then, x=0; & x=-1 sin is at radian -3/4pi and pi
anonymous
  • anonymous
u substitute x value in sin(x) and -1 is co-terminal (270) angle and 0

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