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grantmasini
 one year ago
Limits
grantmasini
 one year ago
Limits

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grantmasini
 one year ago
Best ResponseYou've already chosen the best response.0\[\cos x \lim_{h \rightarrow 0}\frac{ \sin h }{ h }\]

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0have you learned lhospital rule ?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0what are you doing in class?

grantmasini
 one year ago
Best ResponseYou've already chosen the best response.0this is one of the last steps in a limit problem from the first unit (limits). it's supposed to evaluate to cosx*1=cosx. I don't understand how sinh/h comes out to be 1?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0well, there is a thing called La'Hospital rule, that says when you run a limit and get 0/0 you can take the derivative of the top and the derivative of the bottom and then run the limit again so your limit lim of sin(h)/h = lim of cos(h)/1 = lim cos(h) and at 0 that is 1

grantmasini
 one year ago
Best ResponseYou've already chosen the best response.0lol, we are on the first unit. haven't learned derivates, or any of the theorems or rules.

grantmasini
 one year ago
Best ResponseYou've already chosen the best response.0can someone just explain how the limit of sinh/h is 1?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0do you know the squeeze theorem?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0There is a geometric proof http://www.youtube.com/watch?v=Ve99biD1KtA I don't know of an elementary way of showing this limit without geometry and quite a bit of explaining...watch that video.

PROSS
 one year ago
Best ResponseYou've already chosen the best response.0It appears that you are beginning the study of Calculus with the topic of limits. We often will use a table of values as they approach the limit from the left and from the right. This is the first method you may want to use. A second method that is used is to look at the graph of the function. You can easily see that the limit as h approaches 0 from the left and right is 1. I hope this helps.
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