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grantmasini
 2 years ago
Limits
grantmasini
 2 years ago
Limits

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grantmasini
 2 years ago
Best ResponseYou've already chosen the best response.0\[\cos x \lim_{h \rightarrow 0}\frac{ \sin h }{ h }\]

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.0have you learned lhospital rule ?

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.0what are you doing in class?

grantmasini
 2 years ago
Best ResponseYou've already chosen the best response.0this is one of the last steps in a limit problem from the first unit (limits). it's supposed to evaluate to cosx*1=cosx. I don't understand how sinh/h comes out to be 1?

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.0well, there is a thing called La'Hospital rule, that says when you run a limit and get 0/0 you can take the derivative of the top and the derivative of the bottom and then run the limit again so your limit lim of sin(h)/h = lim of cos(h)/1 = lim cos(h) and at 0 that is 1

grantmasini
 2 years ago
Best ResponseYou've already chosen the best response.0lol, we are on the first unit. haven't learned derivates, or any of the theorems or rules.

grantmasini
 2 years ago
Best ResponseYou've already chosen the best response.0can someone just explain how the limit of sinh/h is 1?

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.0do you know the squeeze theorem?

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.0There is a geometric proof http://www.youtube.com/watch?v=Ve99biD1KtA I don't know of an elementary way of showing this limit without geometry and quite a bit of explaining...watch that video.

PROSS
 2 years ago
Best ResponseYou've already chosen the best response.0It appears that you are beginning the study of Calculus with the topic of limits. We often will use a table of values as they approach the limit from the left and from the right. This is the first method you may want to use. A second method that is used is to look at the graph of the function. You can easily see that the limit as h approaches 0 from the left and right is 1. I hope this helps.
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