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burhan101
 one year ago
A cylindrical can is made to hold 500 mL of soup. Determine the dimensions of the can that will minimize the amount of metal required.
burhan101
 one year ago
A cylindrical can is made to hold 500 mL of soup. Determine the dimensions of the can that will minimize the amount of metal required.

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zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Volume of a Cylinder:\[\large V=\pi r^2h\] They want us to minimize the `amount of metal`. The amount of metal is the `Surface Area`. Surface Area of a Cylinder (If I'm remembering this correctly):\[\large A=2\pi r^2+2 \pi r h\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2They want us to minimize the surface area, given a constraint on the volume.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large 500=\pi r^2h\]Solving for h gives us,\[\large \color{orangered}{h=\frac{500}{\pi r^2}}\] We'll plug this into our Area formula. \[\large A=2\pi r^2+2 \pi r \color{orangered}{h} \qquad\rightarrow\qquad A=2\pi r^2+2 \pi r \color{orangered}{\frac{500}{\pi r^2}}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Simplify it down and then take the derivative of your area function. Then setting it equal to zero will allow you to find critical points, namely the value of r that will minimize the area.

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge A=2 \pi r^2+1000\]

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge 0=4\pi r1000r\]

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0am i doing it right so far (that is the derivative)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2I dunno if you simplified that correct for area. Shouldn't you get something like this? Remember the bottom r is squared. \[\huge A=2 \pi r^2+\frac{1000}{r}\]

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0yes that's what I took the derivative of

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Hmm, your second term looks a little off. We should get something like this, \[\huge A'=4\pi r\frac{1000}{r^2}\] Need to see steps?

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0Nope, i made a mistake in the quotient rule

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0How do i solve for 'x' now?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2For r? Set equal to zero as you did. Then get a common denominator, turn it into one big fraction.

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge 0=\frac{ 4(\pi r^3250) }{ \pi^2 }\] how do i solve for r now @zepdrix

dan815
 one year ago
Best ResponseYou've already chosen the best response.0wut u mean its simple, solve for it, remember pi is just some constant

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge 0=\frac{ 4(\pi r^3250) }{ r^2 }\]Multiply both sides by r^2 giving us,\[\huge 0=4(\pi r^3250)\]Then divide both sides by 4, and solve! :)

dan815
 one year ago
Best ResponseYou've already chosen the best response.0^ he means multiply by pi^2 but u get the point

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2no, he put pi^2 on the bottom as a mistake.

dan815
 one year ago
Best ResponseYou've already chosen the best response.0i was wondering why hed ask for help to solve that xD
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