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burhan101

  • one year ago

[check my work ] A cylindrical container, with a volume of 4000cm³ is being constructed to build candies. The cost of the base and lid is $0.005/cm², and the cost of the side walls is $0.0025/cm². Determine the dimensions of the cheapest possible container. Okay so I finished the problem and got the right radius but i'm having problems finding the height !

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  1. burhan101
    • one year ago
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  2. dan815
    • one year ago
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    whys ur handwriting so neat..

  3. dan815
    • one year ago
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    its hard to read that scan tho

  4. dan815
    • one year ago
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    lets just go over the steps

  5. dan815
    • one year ago
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    tell me what you wrote for your surface area equation and volume equation

  6. dan815
    • one year ago
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    |dw:1371786843467:dw|

  7. dan815
    • one year ago
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    minizmine cost*

  8. dan815
    • one year ago
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    either way u do same functioon lol

  9. dan815
    • one year ago
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    is this what u did?

  10. dan815
    • one year ago
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    u can rewrite h as a function of r or r as a function of h and substitute into 2nd equation and take the derivative solve for the critical points, and see what dimensions minimize cost

  11. burhan101
    • one year ago
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    ill post a better picture cause i have the whole question finished

  12. burhan101
    • one year ago
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    just that last step is missing

  13. burhan101
    • one year ago
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    @dan815

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  14. saloniiigupta95
    • one year ago
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    I don't know what the above discussion is going into, but if you have found out the radius, just substitute the value in pi*r^2*h = 4000 since the volume of cylinder is given by pi*r^2*h...

  15. dan815
    • one year ago
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    yes looks right

  16. dan815
    • one year ago
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    i checked ur first few steps its right upto there

  17. burhan101
    • one year ago
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    mhm but then i have to find h

  18. burhan101
    • one year ago
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    i'm not gettingg the right value for h

  19. saloniiigupta95
    • one year ago
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    @ dan815 |dw:1371790110621:dw| It should be 2 times- one for lid and one for base...

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