[check my work ] A cylindrical container, with a volume of 4000cm³ is being constructed to build candies. The cost of the base and lid is $0.005/cm², and the cost of the side walls is $0.0025/cm². Determine the dimensions of the cheapest possible container. Okay so I finished the problem and got the right radius but i'm having problems finding the height !

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[check my work ] A cylindrical container, with a volume of 4000cm³ is being constructed to build candies. The cost of the base and lid is $0.005/cm², and the cost of the side walls is $0.0025/cm². Determine the dimensions of the cheapest possible container. Okay so I finished the problem and got the right radius but i'm having problems finding the height !

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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whys ur handwriting so neat..
its hard to read that scan tho

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Other answers:

lets just go over the steps
tell me what you wrote for your surface area equation and volume equation
|dw:1371786843467:dw|
minizmine cost*
either way u do same functioon lol
is this what u did?
u can rewrite h as a function of r or r as a function of h and substitute into 2nd equation and take the derivative solve for the critical points, and see what dimensions minimize cost
ill post a better picture cause i have the whole question finished
just that last step is missing
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I don't know what the above discussion is going into, but if you have found out the radius, just substitute the value in pi*r^2*h = 4000 since the volume of cylinder is given by pi*r^2*h...
yes looks right
i checked ur first few steps its right upto there
mhm but then i have to find h
i'm not gettingg the right value for h
@ dan815 |dw:1371790110621:dw| It should be 2 times- one for lid and one for base...

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