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burhan101

Find the derivative

  • 10 months ago
  • 10 months ago

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  1. burhan101
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    \[\huge y=(15d)e^{\frac{ -d }{ 5 }}\]

    • 10 months ago
  2. cwrw238
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    6 penguins on board!

    • 10 months ago
  3. burhan101
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    \[\huge y= (15d)'(e^{\frac{ -d }{ 5 }})+(15d)((e^{\frac{ -d }{ 5 }})'\]

    • 10 months ago
  4. burhan101
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    y'= *

    • 10 months ago
  5. Azteck
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    Are you differentiating with respect to d or x?

    • 10 months ago
  6. Azteck
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    Or is d a constant?

    • 10 months ago
  7. Azteck
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    "d"*

    • 10 months ago
  8. burhan101
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    \[\huge y'= 15(e^{\frac{ -d }{ 5 }})-30d(e^{\frac{ -d }{ 5 }})\]

    • 10 months ago
  9. Azteck
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    Ah sorry, my eyes went somewhere. Sorry about that.

    • 10 months ago
  10. burhan101
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    d is a constant :P

    • 10 months ago
  11. Azteck
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    d is the variable, not a constant.

    • 10 months ago
  12. Azteck
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    and you are almost correct. The 30 is not right.

    • 10 months ago
  13. cwrw238
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    check your second part of your answer

    • 10 months ago
  14. cwrw238
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    (e^(-d/5)' = -(1/5)e*(-d/5)

    • 10 months ago
  15. Azteck
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    @burhan101 are you there? If you are, please read what cwrw238 has written above.

    • 10 months ago
  16. burhan101
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    @cwrw238 im a little confused

    • 10 months ago
  17. burhan101
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    |dw:1371805163917:dw| @Azteck @cwrw238

    • 10 months ago
  18. Azteck
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    \[\frac{1}{5}\times 15=75???\]

    • 10 months ago
  19. Azteck
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    I think you got confusde about 1/5 and 5 when multiplying.

    • 10 months ago
  20. Azteck
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    confused*

    • 10 months ago
  21. burhan101
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    oppps 3*

    • 10 months ago
  22. burhan101
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    |dw:1371805796678:dw|

    • 10 months ago
  23. burhan101
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    @Azteck

    • 10 months ago
  24. Azteck
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    Yep, excellent!

    • 10 months ago
  25. Azteck
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    Well done.

    • 10 months ago
  26. burhan101
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    One more question

    • 10 months ago
  27. burhan101
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    if i solve for d, will i have to use ln ?

    • 10 months ago
  28. burhan101
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    nvm i got it :P

    • 10 months ago
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