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\[\huge y=(15d)e^{\frac{ -d }{ 5 }}\]
6 penguins on board!
\[\huge y= (15d)'(e^{\frac{ -d }{ 5 }})+(15d)((e^{\frac{ -d }{ 5 }})'\]

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Other answers:

y'= *
Are you differentiating with respect to d or x?
Or is d a constant?
\[\huge y'= 15(e^{\frac{ -d }{ 5 }})-30d(e^{\frac{ -d }{ 5 }})\]
Ah sorry, my eyes went somewhere. Sorry about that.
d is a constant :P
d is the variable, not a constant.
and you are almost correct. The 30 is not right.
check your second part of your answer
(e^(-d/5)' = -(1/5)e*(-d/5)
@burhan101 are you there? If you are, please read what cwrw238 has written above.
@cwrw238 im a little confused
|dw:1371805163917:dw| @Azteck @cwrw238
\[\frac{1}{5}\times 15=75???\]
I think you got confusde about 1/5 and 5 when multiplying.
oppps 3*
Yep, excellent!
Well done.
One more question
if i solve for d, will i have to use ln ?
nvm i got it :P

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