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burhan101Best ResponseYou've already chosen the best response.0
But i dont get how its chain rule
 10 months ago

burhan101Best ResponseYou've already chosen the best response.0
its tanx² not (tanx)² :S
 10 months ago

Jack1Best ResponseYou've already chosen the best response.2
The chain rule can be applied to composites of more than two functions. consider : \[y = \tan (x ^{2})\] as: \[y = f(u) = \tan (u)\] and \[u = g(x) = x ^{2}\]
 10 months ago

Jack1Best ResponseYou've already chosen the best response.2
so first of all, how are your derivative skills? whats the derivative of g(x) above...?
 10 months ago

Jack1Best ResponseYou've already chosen the best response.2
@burhan101 ... whats the derivative of u... ? (thats the g(x) one)...
 10 months ago

Jack1Best ResponseYou've already chosen the best response.2
yeah, pretty much... but in this case u refers to the function g(x) which is x^2 is derivative of u = 2x... not 2u, you got the right idea tho ;)
 10 months ago

Jack1Best ResponseYou've already chosen the best response.2
cool, next we do the derivative of tan (u) (answwer in this case will contain a U)
 10 months ago

Jack1Best ResponseYou've already chosen the best response.2
so derivative of f(u) =...?
 10 months ago

Jack1Best ResponseYou've already chosen the best response.2
k, if u come back, its a chain rule problem, so: differentiate x^2 (2x) then differentiate tan x^2 (derivative of tan = sec^2) and multiply your results \[y' = 2x \times \sec ^{2}(x ^{2})\]
 10 months ago
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