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burhan101
 one year ago
Best ResponseYou've already chosen the best response.0But i dont get how its chain rule

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0its tanx² not (tanx)² :S

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2The chain rule can be applied to composites of more than two functions. consider : \[y = \tan (x ^{2})\] as: \[y = f(u) = \tan (u)\] and \[u = g(x) = x ^{2}\]

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2so first of all, how are your derivative skills? whats the derivative of g(x) above...?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2@burhan101 ... whats the derivative of u... ? (thats the g(x) one)...

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2yeah, pretty much... but in this case u refers to the function g(x) which is x^2 is derivative of u = 2x... not 2u, you got the right idea tho ;)

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2cool, next we do the derivative of tan (u) (answwer in this case will contain a U)

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2so derivative of f(u) =...?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2k, if u come back, its a chain rule problem, so: differentiate x^2 (2x) then differentiate tan x^2 (derivative of tan = sec^2) and multiply your results \[y' = 2x \times \sec ^{2}(x ^{2})\]
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