Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Please Help! Parameterize the plane that contains the three points (3,−5,−2), (10,−12,−10), and (25,0,5). r(s,t)=

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

I first assigned the points to P Q and R and then found PQ and PR and then put P+u+v and I got <3+7s+22t,-5-7s+5t,-2-8s+7s> but got it wrong!
what did you get for vector PQ
btw, this page may help you out http://math.harvard.edu/~ytzeng/worksheet/0926_sol.pdf see page 3

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I got <7,-7,-8>
Yes i looked at that and Im stll not sure what i dd wrong
how about PR?
22,5,7
ok, so far, so good
I'm assuming you tried <3+7s+22t,-5-7s+5t,-2-8s+7t>and not <3+7s+22t,-5-7s+5t,-2-8s+7s> right?
i did it twice and got it wrong twice
ok one sec
does it specify at all which variables are the free variables (like x and y or x and z)?
no
hmm well I managed to find a calculator that will give the equation of the plane
http://www.wolframalpha.com/input/?i=plane+through+points+%283%2C%E2%88%925%2C%E2%88%922%29%2C+%2810%2C%E2%88%9212%2C%E2%88%9210%29%2C+and+%2825%2C0%2C5%29
that equation is -x-25y+21z-80 = 0 -x-25y+21z= 80 solve for x: -x-25y+21z= 80 -x = 80+25y-21z x = -80-25y+21z
so if you let y = s and z = t, then you will get = <-80-25y+21z, y, z> = <-80-25s+21t, s, t>
unfortunately there are many ways to parameterize the plane
can you please provide me with an example
what do you mean
as in please show me a way o parameterize this
well you could take the cross product of vectors PQ and PR
that will give you the normal vector to the plane
what would i do then
what do you get when you do the cross product
gimme a sec
-89i+113j+189k
somewhat close, but that's not correct
what is it then?
try it again
ok

Not the answer you are looking for?

Search for more explanations.

Ask your own question