I first assigned the points to P Q and R and then found PQ and PR and then put P+u
+v and I got <3+7s+22t,-5-7s+5t,-2-8s+7s> but got it wrong!
what did you get for vector PQ
btw, this page may help you out http://math.harvard.edu/~ytzeng/worksheet/0926_sol.pdf see page 3
I got <7,-7,-8>
Yes i looked at that and Im stll not sure what i dd wrong
how about PR?
ok, so far, so good
I'm assuming you tried <3+7s+22t,-5-7s+5t,-2-8s+7t>and not <3+7s+22t,-5-7s+5t,-2-8s+7s> right?
i did it twice and got it wrong twice
ok one sec
does it specify at all which variables are the free variables (like x and y or x and z)?
hmm well I managed to find a calculator that will give the equation of the plane
that equation is -x-25y+21z-80 = 0 -x-25y+21z= 80 solve for x: -x-25y+21z= 80 -x = 80+25y-21z x = -80-25y+21z
so if you let y = s and z = t, then you will get
= <-80-25y+21z, y, z>
= <-80-25s+21t, s, t>
unfortunately there are many ways to parameterize the plane
can you please provide me with an example
what do you mean
as in please show me a way o parameterize this
well you could take the cross product of vectors PQ and PR
that will give you the normal vector to the plane
what would i do then
what do you get when you do the cross product
gimme a sec
somewhat close, but that's not correct
what is it then?
try it again