wilks311 2 years ago (x-5)(x+3)=33 ; find the real roots

1. cwrw238

(x-5)(x+3)=33 x^2 - 2x - 15 = 33 x^2 - 2x - 48 = 0 can u continue from here?

2. wilks311

3. cwrw238

yw

4. wilks311

Ah another question. Havent done this stuff in 4 years.

5. wilks311

(x+2)^2(x-1)+(x+2)(x-1)^2

6. whpalmer4

\[(x+2)^2(x-1) + (x+2)(x-1)^2\]multiply it out, step by step: \[(x+2)^2 = (x+2)(x+2) = x^2+2x+2x+4 = x^2+4x+4\] \[(x^2+2x+4)(x-1) = x^3-x^2+2x^2-2x+4x-4 = x^3+x^2+2x-4\] \[x^3+x^2+2x-4 + (x+2)(x-1)^2\]you do the rest, then simplify

7. wilks311

I've gotten down to 2x^3+3x^2-11x-2 Any help factoring that please?

8. whpalmer4

@cwrw238 pretty sure that those 2s outside parentheses are supposed to be ^2

9. cwrw238

yea - u r right

10. cwrw238

i'm embarrassed!!

11. whpalmer4

life would be easier if openstudiers couldn't copy and paste the questions, losing all of those valuable positional clues :-)

12. cwrw238

yea

13. wilks311

Guys , you didnt need to expand!

14. whpalmer4

we didn't need to do anything, really :-)

15. wilks311

just do something similar like a^2v +ab^2 = ab(a+b) then solve!

16. wilks311

gah im hitting myself >:(