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jazzyfa30

  • one year ago

Solve: | 4x | = |15+x| | 5 | |2y - 1| Select one: a. |5 3| b. |-3 -4| c. | 3 4| d. | -2 5|

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  1. jazzyfa30
    • one year ago
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    @jagatuba help please

  2. jdoe0001
    • one year ago
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    can you take a quick screenshot of the material and show us?

  3. jagatuba
    • one year ago
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    Sorry, I'm at work and got interrupted. Hmm. I'm missing something I think. -3 and 5 would be the solution to |4x|=|15+x|, but I don't see that as an answer possibility. Like jdoe said maybe a screen shot would help.

  4. jazzyfa30
    • one year ago
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    how do i take a screenshot

  5. jagatuba
    • one year ago
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    I'm not seeing a relationship between | 4x | = |15+x| and | 5 | |2y - 1|, but my math skills are a little bit rusty I'm ashamed to admit.

  6. jdoe0001
    • one year ago
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    usually tap the PrinsScrn or PrtSc button after the F12 key on the keyboard, then go to say Paint, and paste there

  7. jagatuba
    • one year ago
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    The Prt Sc button will copy the screen to the clipboard then paste that into Paint and save the file then attach that file to your response with the attach file button below your response box.

  8. jagatuba
    • one year ago
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    LOL Yeah what he said.

  9. jazzyfa30
    • one year ago
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  10. jazzyfa30
    • one year ago
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    thank you for showing me that

  11. jazzyfa30
    • one year ago
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    i got my answer it was A

  12. jagatuba
    • one year ago
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    Now I'm just trying to figure out why it's |5 3| rather than 5 -3

  13. jazzyfa30
    • one year ago
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    i dont even know how 5 got in the answer

  14. jagatuba
    • one year ago
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    Well if x=5 then 4x=20 and 15+x=20 therefore 4x=15+x. Likewise if x=-3 then |4x|=|-12| or simply 12 and |15+x|=|12| or simply 12.

  15. jagatuba
    • one year ago
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    However, if x=3 then 4x=12 and 15+3=18, therefore |4x|≠|15+x|.

  16. jazzyfa30
    • one year ago
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    oh ok

  17. jagatuba
    • one year ago
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    Where is @mathslover when you need'm?

  18. jazzyfa30
    • one year ago
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    I need your help on another problem

  19. mathslover
    • one year ago
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    Hello Jagatuba, awesome help ! Sorry, I was away.

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