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jazzyfa30 Group Title

Solve: | 4x | = |15+x| | 5 | |2y - 1| Select one: a. |5 3| b. |-3 -4| c. | 3 4| d. | -2 5|

  • one year ago
  • one year ago

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  1. jazzyfa30 Group Title
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    @jagatuba help please

    • one year ago
  2. jdoe0001 Group Title
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    can you take a quick screenshot of the material and show us?

    • one year ago
  3. jagatuba Group Title
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    Sorry, I'm at work and got interrupted. Hmm. I'm missing something I think. -3 and 5 would be the solution to |4x|=|15+x|, but I don't see that as an answer possibility. Like jdoe said maybe a screen shot would help.

    • one year ago
  4. jazzyfa30 Group Title
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    how do i take a screenshot

    • one year ago
  5. jagatuba Group Title
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    I'm not seeing a relationship between | 4x | = |15+x| and | 5 | |2y - 1|, but my math skills are a little bit rusty I'm ashamed to admit.

    • one year ago
  6. jdoe0001 Group Title
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    usually tap the PrinsScrn or PrtSc button after the F12 key on the keyboard, then go to say Paint, and paste there

    • one year ago
  7. jagatuba Group Title
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    The Prt Sc button will copy the screen to the clipboard then paste that into Paint and save the file then attach that file to your response with the attach file button below your response box.

    • one year ago
  8. jagatuba Group Title
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    LOL Yeah what he said.

    • one year ago
  9. jazzyfa30 Group Title
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    • one year ago
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  10. jazzyfa30 Group Title
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    thank you for showing me that

    • one year ago
  11. jazzyfa30 Group Title
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    i got my answer it was A

    • one year ago
  12. jagatuba Group Title
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    Now I'm just trying to figure out why it's |5 3| rather than 5 -3

    • one year ago
  13. jazzyfa30 Group Title
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    i dont even know how 5 got in the answer

    • one year ago
  14. jagatuba Group Title
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    Well if x=5 then 4x=20 and 15+x=20 therefore 4x=15+x. Likewise if x=-3 then |4x|=|-12| or simply 12 and |15+x|=|12| or simply 12.

    • one year ago
  15. jagatuba Group Title
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    However, if x=3 then 4x=12 and 15+3=18, therefore |4x|≠|15+x|.

    • one year ago
  16. jazzyfa30 Group Title
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    oh ok

    • one year ago
  17. jagatuba Group Title
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    Where is @mathslover when you need'm?

    • one year ago
  18. jazzyfa30 Group Title
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    I need your help on another problem

    • one year ago
  19. mathslover Group Title
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    Hello Jagatuba, awesome help ! Sorry, I was away.

    • one year ago
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