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rim

  • 2 years ago

Solve. x2 – x = 0 x = 0 x = 1 and x = –1 x = 0 and x = –1 x = 0 and x = 1

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  1. cwrw238
    • 2 years ago
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    first factor the LHS x(x - 1) = 0

  2. Jhannybean
    • 2 years ago
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    \[\large x^2-x = 0\] factor out an x from this,since it your LCM.\[\large x(x-1)=0\] Now solve for both values. \[\large x=0\]\[\large x-1=0\]

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