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thomaster Group Title

I need to rewrite a formula

  • one year ago
  • one year ago

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  1. thomaster Group Title
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    \(\huge q=\left(\frac{25}{25+8.8*10}\right)^3~=\LARGE 0.0108\) Now i need to calculate what's 10 in this one for another formula without the 3th powe. \(\LARGE 0.0108\huge =\left(\frac{25}{25+8.8*V_{org}}\right)\) I know the answer is 260 by solving for x but how to rewrite this formula to get V org before the equal sign. I was thinking of this: \(\huge V_{org}=\frac{\left(\Huge\frac{25}{25+8.8}\right)}{0.0108}\) But it gives me the wrong answer. What did i do wrong?

    • one year ago
  2. AravindG Group Title
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    \[\LARGE 0.0108\huge =\left(\frac{25}{25+8.8*V_{org}}\right)\] \[\LARGE 25+8.8*V_{org}\huge =\left(\frac{25}{0.0108}\right)\] \[\LARGE 25+8.8*V_{org}\huge =\left(\frac{25}{0.0108}\right)\] \[\LARGE 8.8*V_{org}\huge =\left(\frac{25}{0.0108}\right)-25\] \[\LARGE V_{org}\huge =dfrac{\left(\frac{25}{0.0108}\right)-25}{8.8}\]

    • one year ago
  3. AravindG Group Title
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    neglect last one sorry

    • one year ago
  4. AravindG Group Title
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    \[\LARGE V_{org}\huge =\dfrac{\left(\frac{25}{0.0108}\right)-25}{8.8}\]

    • one year ago
  5. AravindG Group Title
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    ^^That could give you Vorg

    • one year ago
  6. thomaster Group Title
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    Yes it does :) Thanks man

    • one year ago
  7. AravindG Group Title
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    yw :)

    • one year ago
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