## thomaster Group Title I need to rewrite a formula one year ago one year ago

1. thomaster Group Title

$$\huge q=\left(\frac{25}{25+8.8*10}\right)^3~=\LARGE 0.0108$$ Now i need to calculate what's 10 in this one for another formula without the 3th powe. $$\LARGE 0.0108\huge =\left(\frac{25}{25+8.8*V_{org}}\right)$$ I know the answer is 260 by solving for x but how to rewrite this formula to get V org before the equal sign. I was thinking of this: $$\huge V_{org}=\frac{\left(\Huge\frac{25}{25+8.8}\right)}{0.0108}$$ But it gives me the wrong answer. What did i do wrong?

2. AravindG Group Title

$\LARGE 0.0108\huge =\left(\frac{25}{25+8.8*V_{org}}\right)$ $\LARGE 25+8.8*V_{org}\huge =\left(\frac{25}{0.0108}\right)$ $\LARGE 25+8.8*V_{org}\huge =\left(\frac{25}{0.0108}\right)$ $\LARGE 8.8*V_{org}\huge =\left(\frac{25}{0.0108}\right)-25$ $\LARGE V_{org}\huge =dfrac{\left(\frac{25}{0.0108}\right)-25}{8.8}$

3. AravindG Group Title

neglect last one sorry

4. AravindG Group Title

$\LARGE V_{org}\huge =\dfrac{\left(\frac{25}{0.0108}\right)-25}{8.8}$

5. AravindG Group Title

^^That could give you Vorg

6. thomaster Group Title

Yes it does :) Thanks man

7. AravindG Group Title

yw :)