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anonymous
 3 years ago
How would you go about solving this equation?
anonymous
 3 years ago
How would you go about solving this equation?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[xy \prime  y = 2(xy)^{1/2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know u can use both the homogeneous approach and the Bernoulli method here, but i cant seem to get the right answer.

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\[xy^\prime  y = 2(xy)^{1/2}\\y'=\frac{2(xy)^{1/2}y}x\\=2(y/x)^{1/2}y/x\]

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.1Uh, there's a mistake in there, I'm afraid... \[xy'  y = 2(xy)^{1/2}\] xy' = 2(xy)^{1/2}+y\] \[y' = \frac{2(xy)^{1/2}+y}{x} = 2(y/x)^{1/2}\color{red}{+}y/x\]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1ah yes, thanks for spotting that @whpalmer4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, just noticed. thanks!
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