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This is one requires substitution, but i don't what i am doing wrong...

Differential Equations
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\[yy \prime+x=(x ^{2}+y ^{2})^{1/2}\]
i tried subsitituting \[u = x ^{2}+y ^{2}\]

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Other answers:

why did you think of that substitution?
because it would simplify the right side tremendously...but not too sure.
but what would y' become?
\[(1/y)((du/dx)-x)\]
but when i substitute it get very messy.
substitute and try that simplification again
the mess should work it self out
ok thanks!
tell me what you get,
this is what i have so far...
\[1/y \left( (u-x ^{2})^{1/2} - x(u-x ^{2})^{1/2} \right) + x = u ^{1/2}\]
oh wait ....i forgot about that y
got it!
i get c.
thank you very much!
\[u'=√u\]

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