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dinak23

  • one year ago

y=x^2-4x-12 factored is (x-6) (x+2), how do i determine vertex?

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  1. Compassionate
    • one year ago
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    vertex form is y = a(x-h)^2 +k where vertex is (h,k)

  2. dinak23
    • one year ago
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    so how do i put this equation into vertex form?

  3. dinak23
    • one year ago
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    i just dont see where the h and k come in from

  4. dinak23
    • one year ago
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    (x^2-h)^2+k?

  5. eSpeX
    • one year ago
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    'h' and 'k' are just place holders. They, like 'a', can be anything.

  6. dinak23
    • one year ago
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    so how do i find the vertex now? what do i have to put in for h and k

  7. Loser66
    • one year ago
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    |dw:1372118543905:dw|

  8. dinak23
    • one year ago
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    You broke down 12 into a 4 and 8? I see that

  9. dinak23
    • one year ago
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    @loser66 why did you add 4 and subtract 4?

  10. eSpeX
    • one year ago
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    As @Loser66 pointed out, by adding (+4) and subtracting (-4) you are adding 0 to the equation.

  11. dinak23
    • one year ago
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    Is this completing the square?

  12. eSpeX
    • one year ago
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    Similar in principle but not the exact same thing. You are just massaging the equation to fit the form you need, without changing anything.

  13. eSpeX
    • one year ago
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    It's like multiplying two fractions to get a common denominator, or changing both sides of an equation equally, they are all about getting the numbers to "look" like what you need.

  14. dinak23
    • one year ago
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    I see what you guys did now

  15. dinak23
    • one year ago
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    Alright i understand, so the vertex is -2,-16 ?

  16. dinak23
    • one year ago
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    I just checked my answer sheet and thats right! Thanks alot!!

  17. eSpeX
    • one year ago
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    Yes, good job everyone. :D

  18. dinak23
    • one year ago
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    You guys are awesome!

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