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Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0vertex form is y = a(xh)^2 +k where vertex is (h,k)

dinak23
 one year ago
Best ResponseYou've already chosen the best response.0so how do i put this equation into vertex form?

dinak23
 one year ago
Best ResponseYou've already chosen the best response.0i just dont see where the h and k come in from

eSpeX
 one year ago
Best ResponseYou've already chosen the best response.0'h' and 'k' are just place holders. They, like 'a', can be anything.

dinak23
 one year ago
Best ResponseYou've already chosen the best response.0so how do i find the vertex now? what do i have to put in for h and k

dinak23
 one year ago
Best ResponseYou've already chosen the best response.0You broke down 12 into a 4 and 8? I see that

dinak23
 one year ago
Best ResponseYou've already chosen the best response.0@loser66 why did you add 4 and subtract 4?

eSpeX
 one year ago
Best ResponseYou've already chosen the best response.0As @Loser66 pointed out, by adding (+4) and subtracting (4) you are adding 0 to the equation.

dinak23
 one year ago
Best ResponseYou've already chosen the best response.0Is this completing the square?

eSpeX
 one year ago
Best ResponseYou've already chosen the best response.0Similar in principle but not the exact same thing. You are just massaging the equation to fit the form you need, without changing anything.

eSpeX
 one year ago
Best ResponseYou've already chosen the best response.0It's like multiplying two fractions to get a common denominator, or changing both sides of an equation equally, they are all about getting the numbers to "look" like what you need.

dinak23
 one year ago
Best ResponseYou've already chosen the best response.0I see what you guys did now

dinak23
 one year ago
Best ResponseYou've already chosen the best response.0Alright i understand, so the vertex is 2,16 ?

dinak23
 one year ago
Best ResponseYou've already chosen the best response.0I just checked my answer sheet and thats right! Thanks alot!!

eSpeX
 one year ago
Best ResponseYou've already chosen the best response.0Yes, good job everyone. :D
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