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dinak23
Group Title
y=x^24x12 factored is (x6) (x+2), how do i determine vertex?
 one year ago
 one year ago
dinak23 Group Title
y=x^24x12 factored is (x6) (x+2), how do i determine vertex?
 one year ago
 one year ago

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Compassionate Group TitleBest ResponseYou've already chosen the best response.0
vertex form is y = a(xh)^2 +k where vertex is (h,k)
 one year ago

dinak23 Group TitleBest ResponseYou've already chosen the best response.0
so how do i put this equation into vertex form?
 one year ago

dinak23 Group TitleBest ResponseYou've already chosen the best response.0
i just dont see where the h and k come in from
 one year ago

dinak23 Group TitleBest ResponseYou've already chosen the best response.0
(x^2h)^2+k?
 one year ago

eSpeX Group TitleBest ResponseYou've already chosen the best response.0
'h' and 'k' are just place holders. They, like 'a', can be anything.
 one year ago

dinak23 Group TitleBest ResponseYou've already chosen the best response.0
so how do i find the vertex now? what do i have to put in for h and k
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.1
dw:1372118543905:dw
 one year ago

dinak23 Group TitleBest ResponseYou've already chosen the best response.0
You broke down 12 into a 4 and 8? I see that
 one year ago

dinak23 Group TitleBest ResponseYou've already chosen the best response.0
@loser66 why did you add 4 and subtract 4?
 one year ago

eSpeX Group TitleBest ResponseYou've already chosen the best response.0
As @Loser66 pointed out, by adding (+4) and subtracting (4) you are adding 0 to the equation.
 one year ago

dinak23 Group TitleBest ResponseYou've already chosen the best response.0
Is this completing the square?
 one year ago

eSpeX Group TitleBest ResponseYou've already chosen the best response.0
Similar in principle but not the exact same thing. You are just massaging the equation to fit the form you need, without changing anything.
 one year ago

eSpeX Group TitleBest ResponseYou've already chosen the best response.0
It's like multiplying two fractions to get a common denominator, or changing both sides of an equation equally, they are all about getting the numbers to "look" like what you need.
 one year ago

dinak23 Group TitleBest ResponseYou've already chosen the best response.0
I see what you guys did now
 one year ago

dinak23 Group TitleBest ResponseYou've already chosen the best response.0
Alright i understand, so the vertex is 2,16 ?
 one year ago

dinak23 Group TitleBest ResponseYou've already chosen the best response.0
I just checked my answer sheet and thats right! Thanks alot!!
 one year ago

eSpeX Group TitleBest ResponseYou've already chosen the best response.0
Yes, good job everyone. :D
 one year ago

dinak23 Group TitleBest ResponseYou've already chosen the best response.0
You guys are awesome!
 one year ago
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