anonymous
  • anonymous
y=x^2-4x-12 factored is (x-6) (x+2), how do i determine vertex?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Compassionate
  • Compassionate
vertex form is y = a(x-h)^2 +k where vertex is (h,k)
anonymous
  • anonymous
so how do i put this equation into vertex form?
anonymous
  • anonymous
i just dont see where the h and k come in from

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More answers

anonymous
  • anonymous
(x^2-h)^2+k?
eSpeX
  • eSpeX
'h' and 'k' are just place holders. They, like 'a', can be anything.
anonymous
  • anonymous
so how do i find the vertex now? what do i have to put in for h and k
Loser66
  • Loser66
|dw:1372118543905:dw|
anonymous
  • anonymous
You broke down 12 into a 4 and 8? I see that
anonymous
  • anonymous
@loser66 why did you add 4 and subtract 4?
eSpeX
  • eSpeX
As @Loser66 pointed out, by adding (+4) and subtracting (-4) you are adding 0 to the equation.
anonymous
  • anonymous
Is this completing the square?
eSpeX
  • eSpeX
Similar in principle but not the exact same thing. You are just massaging the equation to fit the form you need, without changing anything.
eSpeX
  • eSpeX
It's like multiplying two fractions to get a common denominator, or changing both sides of an equation equally, they are all about getting the numbers to "look" like what you need.
anonymous
  • anonymous
I see what you guys did now
anonymous
  • anonymous
Alright i understand, so the vertex is -2,-16 ?
anonymous
  • anonymous
I just checked my answer sheet and thats right! Thanks alot!!
eSpeX
  • eSpeX
Yes, good job everyone. :D
anonymous
  • anonymous
You guys are awesome!

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