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dinak23

y=x^2-4x-12 factored is (x-6) (x+2), how do i determine vertex?

  • 10 months ago
  • 10 months ago

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  1. Compassionate
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    vertex form is y = a(x-h)^2 +k where vertex is (h,k)

    • 10 months ago
  2. dinak23
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    so how do i put this equation into vertex form?

    • 10 months ago
  3. dinak23
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    i just dont see where the h and k come in from

    • 10 months ago
  4. dinak23
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    (x^2-h)^2+k?

    • 10 months ago
  5. eSpeX
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    'h' and 'k' are just place holders. They, like 'a', can be anything.

    • 10 months ago
  6. dinak23
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    so how do i find the vertex now? what do i have to put in for h and k

    • 10 months ago
  7. Loser66
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    |dw:1372118543905:dw|

    • 10 months ago
  8. dinak23
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    You broke down 12 into a 4 and 8? I see that

    • 10 months ago
  9. dinak23
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    @loser66 why did you add 4 and subtract 4?

    • 10 months ago
  10. eSpeX
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    As @Loser66 pointed out, by adding (+4) and subtracting (-4) you are adding 0 to the equation.

    • 10 months ago
  11. dinak23
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    Is this completing the square?

    • 10 months ago
  12. eSpeX
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    Similar in principle but not the exact same thing. You are just massaging the equation to fit the form you need, without changing anything.

    • 10 months ago
  13. eSpeX
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    It's like multiplying two fractions to get a common denominator, or changing both sides of an equation equally, they are all about getting the numbers to "look" like what you need.

    • 10 months ago
  14. dinak23
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    I see what you guys did now

    • 10 months ago
  15. dinak23
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    Alright i understand, so the vertex is -2,-16 ?

    • 10 months ago
  16. dinak23
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    I just checked my answer sheet and thats right! Thanks alot!!

    • 10 months ago
  17. eSpeX
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    Yes, good job everyone. :D

    • 10 months ago
  18. dinak23
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    You guys are awesome!

    • 10 months ago
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