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schi1

  • 2 years ago

what is the derivative of (x-1)^2(x-3)? I keep expanding it all out to get x^3-5x^2+6x-3 and then finding the derivative of that but I am wrong. So what is it?

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  1. cwrw238
    • 2 years ago
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    you can use the product rule d(x-1)^2 d(x-3) ------- * (x-3) + ----- * (x-1)^2 dx dx

  2. schi1
    • 2 years ago
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    uhh... so we would find the derivative of (x-3) and multiply it too (x-1)^2 then take the derivative of (x-1)^2 and multiply it by (x-3?

  3. cwrw238
    • 2 years ago
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    = 2(x - 1)(x - 3) + (x - 1)^2

  4. cwrw238
    • 2 years ago
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    yes

  5. schi1
    • 2 years ago
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    so it would be (x-1)^2(1)+(x-3)(2(x-1))?

  6. cwrw238
    • 2 years ago
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    d(uv) / dx = u (dv/dx ) + v (du/dx) where u and v are functions of x

  7. schi1
    • 2 years ago
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    so... did I get it right?

  8. cwrw238
    • 2 years ago
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    right

  9. schi1
    • 2 years ago
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    yessssss thanks, I find these rules annoying yet helpful lol

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