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anonymous
 3 years ago
Identify the 42nd term of an arithmetic sequence where a1 = 12 and a27 = 66
anonymous
 3 years ago
Identify the 42nd term of an arithmetic sequence where a1 = 12 and a27 = 66

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i keep coming up with 126 but my options are 70,72,111,114. PLEASE HELP

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1372218335949:dw

Jhannybean
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large a_{n}= a_{1}+(n1)d\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0find r and then just plug in that first equation

Jhannybean
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large 66 =12+(271)d \]\[\large 66= 12 +26d\]\[\large 78 = 26d\]\[\large d= 3\] \[\large a_{42} = 12 + 3(421)\]\[\large a_{42} = 12 + 123\]\[\large a_{42} = 111\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i have no idea what i was doing wrong... but thank you
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