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SnuggieLad Group TitleBest ResponseYou've already chosen the best response.0
Where are you stuck?
 one year ago

SnuggieLad Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ x }{ (x1) }\frac{2x}{x^21}\]
 one year ago

CubiCal Group TitleBest ResponseYou've already chosen the best response.0
I'm pretty sure there is some factoring int there, but I'm not sure.
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
You will want to factor the denominator of that second term. Then you will want to get the LCM (Least Common Multiple) for both terms.
 one year ago

CubiCal Group TitleBest ResponseYou've already chosen the best response.0
Right! So what do I multiply to get 1 and adds up to be 1?
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Hint: the denominator of the second term is the difference of 2 perfect squares.
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Once you factor that denominator of that second term, you will see one of the factors as the denominator in the first term. Take the OTHER factor of the denominator of the second term and make a factor of "1" out of it (by putting the factor in the top and bottom) and multiply the first term by that. Then you will have a common denominator.
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
So to start, can you factor x^2  1 ?
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Another hint:\[a ^{2}  b ^{2} = (a + b)(a  b)\]
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Think of 1 as 1^2
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
If you substitute a=x and b=1 into the equation I wrote out, you should be able to factor:\[x ^{2}  1\]
 one year ago

CubiCal Group TitleBest ResponseYou've already chosen the best response.0
Okay, so my final answer would be x^2x/x^21?
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
No, but that's a good intermediate answer. You need to factor out "x1" from the top and bottom.
 one year ago

CubiCal Group TitleBest ResponseYou've already chosen the best response.0
uh.. x/x1?._.
 one year ago

CubiCal Group TitleBest ResponseYou've already chosen the best response.0
Or would it be +1?
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ x }{ x  1 }  \frac{ 2x }{ x ^{2}  1 } = \frac{ x }{ x  1 }  \frac{ 2x }{ (x  1)(x + 1) } \] \[\frac{ x(x + 1) }{ (x  1)(x + 1) }  \frac{ 2x }{ (x  1)(x + 1) } = \frac{ x ^{2} + x  2x }{ (x  1)(x + 1) }\] \[\frac{ x ^{2}  x }{ (x  1)(x + 1) } = \frac{ x\cancel{(x  1)} }{ \cancel{(x  1)}{(x + 1)} }\]
 one year ago

CubiCal Group TitleBest ResponseYou've already chosen the best response.0
Ohhhh! Okay thanks!
 one year ago

CubiCal Group TitleBest ResponseYou've already chosen the best response.0
Would you mind helping me with some other problems? My teacher isn't available.
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
ok, see you in another question!
 one year ago
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