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Where are you stuck?

\[\frac{ x }{ (x-1) }-\frac{2x}{x^2-1}\]

I'm pretty sure there is some factoring int there, but I'm not sure.

Right! So what do I multiply to get 1 and adds up to be 1?

Hint: the denominator of the second term is the difference of 2 perfect squares.

So to start, can you factor
x^2 - 1
?

Another hint:\[a ^{2} - b ^{2} = (a + b)(a - b)\]

Think of 1 as 1^2

Okay, so my final answer would be x^2-x/x^2-1?

No, but that's a good intermediate answer. You need to factor out "x-1" from the top and bottom.

uh.. x/x-1?._.

Or would it be +1?

Ohhhh! Okay thanks!

uw!

Would you mind helping me with some other problems? My teacher isn't available.

ok, see you in another question!

Okay!