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SnuggieLadBest ResponseYou've already chosen the best response.0
Where are you stuck?
 9 months ago

SnuggieLadBest ResponseYou've already chosen the best response.0
\[\frac{ x }{ (x1) }\frac{2x}{x^21}\]
 9 months ago

CubiCalBest ResponseYou've already chosen the best response.0
I'm pretty sure there is some factoring int there, but I'm not sure.
 9 months ago

tcarroll010Best ResponseYou've already chosen the best response.1
You will want to factor the denominator of that second term. Then you will want to get the LCM (Least Common Multiple) for both terms.
 9 months ago

CubiCalBest ResponseYou've already chosen the best response.0
Right! So what do I multiply to get 1 and adds up to be 1?
 9 months ago

tcarroll010Best ResponseYou've already chosen the best response.1
Hint: the denominator of the second term is the difference of 2 perfect squares.
 9 months ago

tcarroll010Best ResponseYou've already chosen the best response.1
Once you factor that denominator of that second term, you will see one of the factors as the denominator in the first term. Take the OTHER factor of the denominator of the second term and make a factor of "1" out of it (by putting the factor in the top and bottom) and multiply the first term by that. Then you will have a common denominator.
 9 months ago

tcarroll010Best ResponseYou've already chosen the best response.1
So to start, can you factor x^2  1 ?
 9 months ago

tcarroll010Best ResponseYou've already chosen the best response.1
Another hint:\[a ^{2}  b ^{2} = (a + b)(a  b)\]
 9 months ago

tcarroll010Best ResponseYou've already chosen the best response.1
If you substitute a=x and b=1 into the equation I wrote out, you should be able to factor:\[x ^{2}  1\]
 9 months ago

CubiCalBest ResponseYou've already chosen the best response.0
Okay, so my final answer would be x^2x/x^21?
 9 months ago

tcarroll010Best ResponseYou've already chosen the best response.1
No, but that's a good intermediate answer. You need to factor out "x1" from the top and bottom.
 9 months ago

tcarroll010Best ResponseYou've already chosen the best response.1
\[\frac{ x }{ x  1 }  \frac{ 2x }{ x ^{2}  1 } = \frac{ x }{ x  1 }  \frac{ 2x }{ (x  1)(x + 1) } \] \[\frac{ x(x + 1) }{ (x  1)(x + 1) }  \frac{ 2x }{ (x  1)(x + 1) } = \frac{ x ^{2} + x  2x }{ (x  1)(x + 1) }\] \[\frac{ x ^{2}  x }{ (x  1)(x + 1) } = \frac{ x\cancel{(x  1)} }{ \cancel{(x  1)}{(x + 1)} }\]
 9 months ago

CubiCalBest ResponseYou've already chosen the best response.0
Would you mind helping me with some other problems? My teacher isn't available.
 9 months ago

tcarroll010Best ResponseYou've already chosen the best response.1
ok, see you in another question!
 9 months ago
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