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SnuggieLad
 one year ago
Best ResponseYou've already chosen the best response.0Where are you stuck?

SnuggieLad
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ x }{ (x1) }\frac{2x}{x^21}\]

CubiCal
 one year ago
Best ResponseYou've already chosen the best response.0I'm pretty sure there is some factoring int there, but I'm not sure.

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1You will want to factor the denominator of that second term. Then you will want to get the LCM (Least Common Multiple) for both terms.

CubiCal
 one year ago
Best ResponseYou've already chosen the best response.0Right! So what do I multiply to get 1 and adds up to be 1?

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1Hint: the denominator of the second term is the difference of 2 perfect squares.

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1Once you factor that denominator of that second term, you will see one of the factors as the denominator in the first term. Take the OTHER factor of the denominator of the second term and make a factor of "1" out of it (by putting the factor in the top and bottom) and multiply the first term by that. Then you will have a common denominator.

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1So to start, can you factor x^2  1 ?

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1Another hint:\[a ^{2}  b ^{2} = (a + b)(a  b)\]

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1If you substitute a=x and b=1 into the equation I wrote out, you should be able to factor:\[x ^{2}  1\]

CubiCal
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so my final answer would be x^2x/x^21?

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1No, but that's a good intermediate answer. You need to factor out "x1" from the top and bottom.

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ x }{ x  1 }  \frac{ 2x }{ x ^{2}  1 } = \frac{ x }{ x  1 }  \frac{ 2x }{ (x  1)(x + 1) } \] \[\frac{ x(x + 1) }{ (x  1)(x + 1) }  \frac{ 2x }{ (x  1)(x + 1) } = \frac{ x ^{2} + x  2x }{ (x  1)(x + 1) }\] \[\frac{ x ^{2}  x }{ (x  1)(x + 1) } = \frac{ x\cancel{(x  1)} }{ \cancel{(x  1)}{(x + 1)} }\]

CubiCal
 one year ago
Best ResponseYou've already chosen the best response.0Would you mind helping me with some other problems? My teacher isn't available.

tcarroll010
 one year ago
Best ResponseYou've already chosen the best response.1ok, see you in another question!
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