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mariadelia27 Group Title

A 10 gram sample of a substance that's used to detect explosives has a k-value of 0.1353. Find the subtance's half-life, in days.round to the nearest hundreds

  • one year ago
  • one year ago

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  1. RaphaelFilgueiras Group Title
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    you shoud try to ask it in chemistry section

    • one year ago
  2. mariadelia27 Group Title
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    ok thanks it scause i really need this answer

    • one year ago
  3. RaphaelFilgueiras Group Title
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    do you have the formula?

    • one year ago
  4. mariadelia27 Group Title
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    n=Noe^kt

    • one year ago
  5. RaphaelFilgueiras Group Title
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    n is moles?

    • one year ago
  6. mariadelia27 Group Title
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    i need to round to the nearest hundreds too

    • one year ago
  7. RaphaelFilgueiras Group Title
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    what is the unity of k?

    • one year ago
  8. swissgirl Group Title
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    What does k represent?

    • one year ago
  9. mariadelia27 Group Title
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    a positive constant that depends on the substance itself and on the units used to measure time

    • one year ago
  10. RaphaelFilgueiras Group Title
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    5=10*e^(Kt), but what unity of time? seconds^-1?

    • one year ago
  11. swissgirl Group Title
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    Its in days

    • one year ago
  12. mariadelia27 Group Title
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    there a picture of the question

    • one year ago
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  13. RaphaelFilgueiras Group Title
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    and probally the formula is e^(-kt)

    • one year ago
  14. mariadelia27 Group Title
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    did you see the picture

    • one year ago
  15. swissgirl Group Title
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    ya its a diff question :)

    • one year ago
  16. mariadelia27 Group Title
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    my bad ill got teh wrong one

    • one year ago
  17. RaphaelFilgueiras Group Title
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    if k is in days^-1 just solve 5=10*e^(-kt), and you will find t

    • one year ago
  18. mariadelia27 Group Title
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    but i dont know how to solve it either -.-

    • one year ago
  19. mariadelia27 Group Title
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    can you help me please i really need it

    • one year ago
  20. RaphaelFilgueiras Group Title
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    ok

    • one year ago
  21. RaphaelFilgueiras Group Title
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    |dw:1372309018511:dw|

    • one year ago
  22. mariadelia27 Group Title
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    so the answer is 0,5

    • one year ago
  23. mariadelia27 Group Title
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    its exponoential decay thats the section were doing

    • one year ago
  24. RaphaelFilgueiras Group Title
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    5.12303

    • one year ago
  25. RaphaelFilgueiras Group Title
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    k=0.1353

    • one year ago
  26. RaphaelFilgueiras Group Title
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    i use that k

    • one year ago
  27. mariadelia27 Group Title
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    yeah k is that

    • one year ago
  28. mariadelia27 Group Title
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    0.1353

    • one year ago
  29. mariadelia27 Group Title
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    it said its wrong -.-

    • one year ago
  30. RaphaelFilgueiras Group Title
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    we have to know thr unity of k

    • one year ago
  31. swissgirl Group Title
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    What did you put the answer as?

    • one year ago
  32. swissgirl Group Title
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    sorry I am not making sense. What did you enter as your answer?

    • one year ago
  33. mariadelia27 Group Title
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    5.12303

    • one year ago
  34. swissgirl Group Title
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    Its to the hundredths place so it should be 5.12

    • one year ago
  35. RaphaelFilgueiras Group Title
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    try 1871.15 days

    • one year ago
  36. RaphaelFilgueiras Group Title
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    im supposing k is in years

    • one year ago
  37. swissgirl Group Title
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    Ohhhh yaaaaa that makes more sense actually

    • one year ago
  38. mariadelia27 Group Title
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    just that its 53% not 51 %

    • one year ago
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  39. mariadelia27 Group Title
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    this is another question can you guys help with this one

    • one year ago
  40. mariadelia27 Group Title
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    please i did it

    • one year ago
  41. mariadelia27 Group Title
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    please !

    • one year ago
  42. mariadelia27 Group Title
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    you guys help me i really did to passs this class tomorrow is my last day

    • one year ago
  43. mariadelia27 Group Title
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    are you guys there ?

    • one year ago
  44. mariadelia27 Group Title
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    heeelp anyone

    • one year ago
  45. RaphaelFilgueiras Group Title
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    6733.44 years

    • one year ago
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