anonymous
  • anonymous
A 10 gram sample of a substance that's used to detect explosives has a k-value of 0.1353. Find the subtance's half-life, in days.round to the nearest hundreds
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
you shoud try to ask it in chemistry section
anonymous
  • anonymous
ok thanks it scause i really need this answer
anonymous
  • anonymous
do you have the formula?

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More answers

anonymous
  • anonymous
n=Noe^kt
anonymous
  • anonymous
n is moles?
anonymous
  • anonymous
i need to round to the nearest hundreds too
anonymous
  • anonymous
what is the unity of k?
swissgirl
  • swissgirl
What does k represent?
anonymous
  • anonymous
a positive constant that depends on the substance itself and on the units used to measure time
anonymous
  • anonymous
5=10*e^(Kt), but what unity of time? seconds^-1?
swissgirl
  • swissgirl
Its in days
anonymous
  • anonymous
there a picture of the question
1 Attachment
anonymous
  • anonymous
and probally the formula is e^(-kt)
anonymous
  • anonymous
did you see the picture
swissgirl
  • swissgirl
ya its a diff question :)
anonymous
  • anonymous
my bad ill got teh wrong one
anonymous
  • anonymous
if k is in days^-1 just solve 5=10*e^(-kt), and you will find t
anonymous
  • anonymous
but i dont know how to solve it either -.-
anonymous
  • anonymous
can you help me please i really need it
anonymous
  • anonymous
ok
anonymous
  • anonymous
|dw:1372309018511:dw|
anonymous
  • anonymous
so the answer is 0,5
anonymous
  • anonymous
its exponoential decay thats the section were doing
anonymous
  • anonymous
5.12303
anonymous
  • anonymous
k=0.1353
anonymous
  • anonymous
i use that k
anonymous
  • anonymous
yeah k is that
anonymous
  • anonymous
0.1353
anonymous
  • anonymous
it said its wrong -.-
anonymous
  • anonymous
we have to know thr unity of k
swissgirl
  • swissgirl
What did you put the answer as?
swissgirl
  • swissgirl
sorry I am not making sense. What did you enter as your answer?
anonymous
  • anonymous
5.12303
swissgirl
  • swissgirl
Its to the hundredths place so it should be 5.12
anonymous
  • anonymous
try 1871.15 days
anonymous
  • anonymous
im supposing k is in years
swissgirl
  • swissgirl
Ohhhh yaaaaa that makes more sense actually
anonymous
  • anonymous
just that its 53% not 51 %
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anonymous
  • anonymous
this is another question can you guys help with this one
anonymous
  • anonymous
please i did it
anonymous
  • anonymous
please !
anonymous
  • anonymous
you guys help me i really did to passs this class tomorrow is my last day
anonymous
  • anonymous
are you guys there ?
anonymous
  • anonymous
heeelp anyone
anonymous
  • anonymous
6733.44 years

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