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greatuserBest ResponseYou've already chosen the best response.0
it took 2hrs for boat to go from a to b with current and 6hrs to go back against curent. assuming constant speed of boat in both directions, how long wil it take raft (with speed equal to speed of curent) to go from a to b?
 9 months ago

hartnnBest ResponseYou've already chosen the best response.1
let the boat (without any current) take 'x' hrs to reach from a to b and the raft (with speed equal to speed of current) take 'y' hrs to reach from a to b when current assist boat, total time taken was 2 hours, so xy= 2 when current was against the boat, time taken was 6hrs , so x+y =6 find 'y' from here :)
 9 months ago

greatuserBest ResponseYou've already chosen the best response.0
that means x=y+2=6y which means y=2? that cant be right though
 9 months ago

hartnnBest ResponseYou've already chosen the best response.1
yeah, i think i have overlooked something speed = distance / time here, distance is same so, speed * time will be constant let their speed be 'a' and 'b' so, (a+b)*2=(ab)*6=distance =d and you need, time taken by raft, = d/b try it!
 9 months ago

greatuserBest ResponseYou've already chosen the best response.0
but d and b are both unknown. how can we solve it?
 9 months ago

greatuserBest ResponseYou've already chosen the best response.0
please help i still don't get it
 9 months ago

greatuserBest ResponseYou've already chosen the best response.0
so far, a= speed of boat b = sped of current 6a6b = 2a + 2b meaning a = 2b
 9 months ago

dumbcowBest ResponseYou've already chosen the best response.1
"d" is an arbitrary distance that is constant for all trips....let d=1 then 1/(a+b) = 2 1/(ab) = 6 a = 2b 1/3b = 2 1/b = 6 > b = 1/6 > d/b = 6 it would take raft 6 hours
 9 months ago

greatuserBest ResponseYou've already chosen the best response.0
oh i get i now thanks a lot
 9 months ago
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