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greatuser Group Title

it took 2hrs

  • one year ago
  • one year ago

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  1. greatuser Group Title
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    it took 2hrs for boat to go from a to b with current and 6hrs to go back against curent. assuming constant speed of boat in both directions, how long wil it take raft (with speed equal to speed of curent) to go from a to b?

    • one year ago
  2. hartnn Group Title
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    let the boat (without any current) take 'x' hrs to reach from a to b and the raft (with speed equal to speed of current) take 'y' hrs to reach from a to b when current assist boat, total time taken was 2 hours, so x-y= 2 when current was against the boat, time taken was 6hrs , so x+y =6 find 'y' from here :)

    • one year ago
  3. greatuser Group Title
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    that means x=y+2=6-y which means y=2? that cant be right though

    • one year ago
  4. hartnn Group Title
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    yeah, i think i have overlooked something speed = distance / time here, distance is same so, speed * time will be constant let their speed be 'a' and 'b' so, (a+b)*2=(a-b)*6=distance =d and you need, time taken by raft, = d/b try it!

    • one year ago
  5. greatuser Group Title
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    but d and b are both unknown. how can we solve it?

    • one year ago
  6. greatuser Group Title
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    please help i still don't get it

    • one year ago
  7. greatuser Group Title
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    so far, a= speed of boat b = sped of current 6a-6b = 2a + 2b meaning a = 2b

    • one year ago
  8. dumbcow Group Title
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    "d" is an arbitrary distance that is constant for all trips....let d=1 then 1/(a+b) = 2 1/(a-b) = 6 a = 2b 1/3b = 2 1/b = 6 --> b = 1/6 --> d/b = 6 it would take raft 6 hours

    • one year ago
  9. greatuser Group Title
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    oh i get i now thanks a lot

    • one year ago
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