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find the point where the normal line to y = x + root x at (4,6) crosses the y-axis.

Mathematics
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  • phi
did you find the equation for the slope of the curve?
wait.. i'll solve for the slope
take the derivative replace \(x\) by \(4\) that gives you the slope take the negative reciprocal, that give you the slope of the normal line use the point slope formula with the point \((4,6)\) to find the equation of the normal line \(y=mx+b\) then \(b\) is where it crosses the y axis

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Other answers:

the value of b is the answer then?
yes, that is the y intecept
ok.. thanks.. i'll try solving for it
  • phi
Here is a plot of the scenario
1 Attachment
thanks! what i got was 31/5 .. is this correct?
  • phi
how ?
i follow the steps satelite gave
  • phi
I think you wandered off the path...
why??
  • phi
see the plot I posted up above
where is the normal line there?
  • phi
the red line
so what do you think is wrong with my answer? is the steps given by satelite somehow have mistakes? i just followed it
  • phi
what did you get for the slope ?
  • phi
first, what did you get for the derivative?
owh wait.. i got a mistake
b = 46/5 .. i believe that is the correct answer now?
  • phi
yes, 9.2 which matches the plot
9.3 :)) thanks so much! help me again.. i'll post a question :)
  • phi
9.3 ?
yes.. divide 46 by 5 right ? then it will be 9... remainder is 15.. that will be 3.. so 9.3?
  • phi
5*9= 45
lol.. i got a mistake again. sorry.. yes.. 9.2

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