Solve the equation. Identify any extraneous solutions.

- ExplainItLikeImFive

Solve the equation. Identify any extraneous solutions.

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- ExplainItLikeImFive

##### 1 Attachment

- ExplainItLikeImFive

A. 6 is a solution to the original equation. The value –5 is an extraneous solution.
B. 6 and 5 are both extraneous solutions.
C. 5 is a solution to the original equation. The value –6 is an extraneous solution.
D. 6 and –5 are solutions.

- dan815

do u know the meaning of extraneous

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## More answers

- ExplainItLikeImFive

That it's unrelated, I think.

- cwrw238

square both sides
x^2 = x+ 30
x^2 -x - 30 = 0
can u solve this?

- ExplainItLikeImFive

Ill try

- cwrw238

extraneous means that although the working out gives it as a solution , it is not possible as a root

- ExplainItLikeImFive

5 and 6?

- cwrw238

not quite
(x - 6)(x + 5) = 0
giving x = 6 , -5

- ExplainItLikeImFive

So what do I do with that?

- cwrw238

well see if these roots are possible by substituting each into the original equation

- cwrw238

eg x = 6
6 = sqrt(6 + 30)
6 = 6 - so that is a genuine root

- ExplainItLikeImFive

So I can eliminate B and C

- cwrw238

yes

- cwrw238

is -5 a solution?

- ExplainItLikeImFive

I dont think so.

- cwrw238

try plugging in -5 for x in the original equation

- cwrw238

- 5 = sqrt (-5 + 30) does that work out?

- ExplainItLikeImFive

No

- cwrw238

what are the square roots of 25?

- cwrw238

5 ANd -5 right?

- ExplainItLikeImFive

Yes

- cwrw238

so its a genuine root

- ExplainItLikeImFive

So they're both genuine making them both solutions.

- cwrw238

right

- ExplainItLikeImFive

I do believe I'd pick D

- cwrw238

correct

- ExplainItLikeImFive

Thank you very much.

- cwrw238

yw

- anonymous

wrong.

- cwrw238

please explain why thats wrong

- anonymous

ask the teacher, I answered D and I got it wrong.

- dan815

hii

- dan815

|dw:1377219675010:dw|

- dan815

is this your question?

- dan815

oh sorry this is your question |dw:1377219778699:dw|

- dan815

your answers are 6 and -5!

- dan815

|dw:1377219879123:dw|

- anonymous

The right answer should be 6 is a solution to the original equation. The value –5 is an extraneous solution.

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