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ExplainItLikeImFive

  • 2 years ago

Solve the equation. Identify any extraneous solutions.

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  1. ExplainItLikeImFive
    • 2 years ago
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  2. ExplainItLikeImFive
    • 2 years ago
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    A. 6 is a solution to the original equation. The value –5 is an extraneous solution. B. 6 and 5 are both extraneous solutions. C. 5 is a solution to the original equation. The value –6 is an extraneous solution. D. 6 and –5 are solutions.

  3. dan815
    • 2 years ago
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    do u know the meaning of extraneous

  4. ExplainItLikeImFive
    • 2 years ago
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    That it's unrelated, I think.

  5. cwrw238
    • 2 years ago
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    square both sides x^2 = x+ 30 x^2 -x - 30 = 0 can u solve this?

  6. ExplainItLikeImFive
    • 2 years ago
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    Ill try

  7. cwrw238
    • 2 years ago
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    extraneous means that although the working out gives it as a solution , it is not possible as a root

  8. ExplainItLikeImFive
    • 2 years ago
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    5 and 6?

  9. cwrw238
    • 2 years ago
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    not quite (x - 6)(x + 5) = 0 giving x = 6 , -5

  10. ExplainItLikeImFive
    • 2 years ago
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    So what do I do with that?

  11. cwrw238
    • 2 years ago
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    well see if these roots are possible by substituting each into the original equation

  12. cwrw238
    • 2 years ago
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    eg x = 6 6 = sqrt(6 + 30) 6 = 6 - so that is a genuine root

  13. ExplainItLikeImFive
    • 2 years ago
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    So I can eliminate B and C

  14. cwrw238
    • 2 years ago
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    yes

  15. cwrw238
    • 2 years ago
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    is -5 a solution?

  16. ExplainItLikeImFive
    • 2 years ago
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    I dont think so.

  17. cwrw238
    • 2 years ago
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    try plugging in -5 for x in the original equation

  18. cwrw238
    • 2 years ago
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    - 5 = sqrt (-5 + 30) does that work out?

  19. ExplainItLikeImFive
    • 2 years ago
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    No

  20. cwrw238
    • 2 years ago
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    what are the square roots of 25?

  21. cwrw238
    • 2 years ago
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    5 ANd -5 right?

  22. ExplainItLikeImFive
    • 2 years ago
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    Yes

  23. cwrw238
    • 2 years ago
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    so its a genuine root

  24. ExplainItLikeImFive
    • 2 years ago
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    So they're both genuine making them both solutions.

  25. cwrw238
    • 2 years ago
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    right

  26. ExplainItLikeImFive
    • 2 years ago
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    I do believe I'd pick D

  27. cwrw238
    • 2 years ago
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    correct

  28. ExplainItLikeImFive
    • 2 years ago
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    Thank you very much.

  29. cwrw238
    • 2 years ago
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    yw

  30. Laaislima
    • one year ago
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    wrong.

  31. cwrw238
    • one year ago
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    please explain why thats wrong

  32. Laaislima
    • one year ago
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    ask the teacher, I answered D and I got it wrong.

  33. dan815
    • one year ago
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    hii

  34. dan815
    • one year ago
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    |dw:1377219675010:dw|

  35. dan815
    • one year ago
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    is this your question?

  36. dan815
    • one year ago
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    oh sorry this is your question |dw:1377219778699:dw|

  37. dan815
    • one year ago
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    your answers are 6 and -5!

  38. dan815
    • one year ago
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    |dw:1377219879123:dw|

  39. Laaislima
    • one year ago
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    The right answer should be 6 is a solution to the original equation. The value –5 is an extraneous solution.

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