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michelle_1216_16

  • one year ago

Julie kicks a moose skin ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting height of the ball is 0 feet. Approximately, how long does it take until the moose skin ball hits the ground again? 0.6 sec 0.8 sec 1.6 secs 2.8 secs please help...

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  1. cwrw238
    • one year ago
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    use the equations of motion with constant accleeration

  2. cwrw238
    • one year ago
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    s = ut + 0.5gt^2

  3. michelle_1216_16
    • one year ago
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    what are the equations if you dont mind:)

  4. cwrw238
    • one year ago
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    s = displacement = 0 g = -32 ft/s62 and u = 25 ft/s

  5. cwrw238
    • one year ago
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    0 = 25t - 16t^2 solve for t

  6. pwnzerer
    • one year ago
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    cwrw238 you are so wrong that newton cam back to life and died again

  7. pwnzerer
    • one year ago
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    @cwrw238

  8. michelle_1216_16
    • one year ago
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    so what would the answer be

  9. pak_asfand
    • one year ago
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    Michelle i would like to help you but i think that the data is incomplete...

  10. michelle_1216_16
    • one year ago
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    but that is how the question is written out what am suppose to do? i could go back and reread the lesson

  11. pwnzerer
    • one year ago
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    yes you should you dont even know what equations of motion are

  12. michelle_1216_16
    • one year ago
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    you see this is my third time taking this class and i really don't want to fail again.

  13. pak_asfand
    • one year ago
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    http://library.thinkquest.org/28388/Mechanics/Motions/Equation.htm

  14. pak_asfand
    • one year ago
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    Ahaha michelle take it easy!

  15. michelle_1216_16
    • one year ago
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    i think I will, look over the lesson again,but what do you guys think would be the best way to approach it.

  16. pwnzerer
    • one year ago
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    with love

  17. michelle_1216_16
    • one year ago
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    :)

  18. pak_asfand
    • one year ago
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    The problem that i am having is the fact that they didnt mention at which point in height the balls stops and starts falling back

  19. michelle_1216_16
    • one year ago
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    yeah, i guess, i could always email my teacher about it because there are alway's glitches like that happening in the tests.

  20. jim_thompson5910
    • one year ago
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    cwrw238 already said it solve 0 = 25t - 16t^2 for t to get your answer (it will be the root that is not 0)

  21. michelle_1216_16
    • one year ago
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    um ok, i will go back and do it that way.

  22. michelle_1216_16
    • one year ago
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    thanks for the advice everyone, you all have been great so you have a nice day

  23. pwnzerer
    • one year ago
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    YOU HAVE TO USE SEQENCES EVERTHING ELSE IS WRONG!!!!!!!!!!!!!!

  24. pak_asfand
    • one year ago
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    Good luck!

  25. cwrw238
    • one year ago
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    16t^2 - 25 = 0 t(16t - 25) = 0 16t = 25 f = 25/16 = 1.6

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