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anonymous
 3 years ago
Julie kicks a moose skin ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting height of the ball is 0 feet. Approximately, how long does it take until the moose skin ball hits the ground again?
0.6 sec
0.8 sec
1.6 secs
2.8 secs
please help...
anonymous
 3 years ago
Julie kicks a moose skin ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting height of the ball is 0 feet. Approximately, how long does it take until the moose skin ball hits the ground again? 0.6 sec 0.8 sec 1.6 secs 2.8 secs please help...

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cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.2use the equations of motion with constant accleeration

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what are the equations if you dont mind:)

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.2s = displacement = 0 g = 32 ft/s62 and u = 25 ft/s

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.20 = 25t  16t^2 solve for t

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cwrw238 you are so wrong that newton cam back to life and died again

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so what would the answer be

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Michelle i would like to help you but i think that the data is incomplete...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but that is how the question is written out what am suppose to do? i could go back and reread the lesson

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes you should you dont even know what equations of motion are

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you see this is my third time taking this class and i really don't want to fail again.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://library.thinkquest.org/28388/Mechanics/Motions/Equation.htm

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ahaha michelle take it easy!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think I will, look over the lesson again,but what do you guys think would be the best way to approach it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The problem that i am having is the fact that they didnt mention at which point in height the balls stops and starts falling back

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah, i guess, i could always email my teacher about it because there are alway's glitches like that happening in the tests.

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0cwrw238 already said it solve 0 = 25t  16t^2 for t to get your answer (it will be the root that is not 0)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0um ok, i will go back and do it that way.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks for the advice everyone, you all have been great so you have a nice day

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0YOU HAVE TO USE SEQENCES EVERTHING ELSE IS WRONG!!!!!!!!!!!!!!

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.216t^2  25 = 0 t(16t  25) = 0 16t = 25 f = 25/16 = 1.6
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