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 one year ago
Julie kicks a moose skin ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting height of the ball is 0 feet. Approximately, how long does it take until the moose skin ball hits the ground again?
0.6 sec
0.8 sec
1.6 secs
2.8 secs
please help...
 one year ago
Julie kicks a moose skin ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting height of the ball is 0 feet. Approximately, how long does it take until the moose skin ball hits the ground again? 0.6 sec 0.8 sec 1.6 secs 2.8 secs please help...

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cwrw238
 one year ago
Best ResponseYou've already chosen the best response.2use the equations of motion with constant accleeration

michelle_1216_16
 one year ago
Best ResponseYou've already chosen the best response.0what are the equations if you dont mind:)

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.2s = displacement = 0 g = 32 ft/s62 and u = 25 ft/s

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.20 = 25t  16t^2 solve for t

pwnzerer
 one year ago
Best ResponseYou've already chosen the best response.1cwrw238 you are so wrong that newton cam back to life and died again

michelle_1216_16
 one year ago
Best ResponseYou've already chosen the best response.0so what would the answer be

pak_asfand
 one year ago
Best ResponseYou've already chosen the best response.1Michelle i would like to help you but i think that the data is incomplete...

michelle_1216_16
 one year ago
Best ResponseYou've already chosen the best response.0but that is how the question is written out what am suppose to do? i could go back and reread the lesson

pwnzerer
 one year ago
Best ResponseYou've already chosen the best response.1yes you should you dont even know what equations of motion are

michelle_1216_16
 one year ago
Best ResponseYou've already chosen the best response.0you see this is my third time taking this class and i really don't want to fail again.

pak_asfand
 one year ago
Best ResponseYou've already chosen the best response.1http://library.thinkquest.org/28388/Mechanics/Motions/Equation.htm

pak_asfand
 one year ago
Best ResponseYou've already chosen the best response.1Ahaha michelle take it easy!

michelle_1216_16
 one year ago
Best ResponseYou've already chosen the best response.0i think I will, look over the lesson again,but what do you guys think would be the best way to approach it.

pak_asfand
 one year ago
Best ResponseYou've already chosen the best response.1The problem that i am having is the fact that they didnt mention at which point in height the balls stops and starts falling back

michelle_1216_16
 one year ago
Best ResponseYou've already chosen the best response.0yeah, i guess, i could always email my teacher about it because there are alway's glitches like that happening in the tests.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0cwrw238 already said it solve 0 = 25t  16t^2 for t to get your answer (it will be the root that is not 0)

michelle_1216_16
 one year ago
Best ResponseYou've already chosen the best response.0um ok, i will go back and do it that way.

michelle_1216_16
 one year ago
Best ResponseYou've already chosen the best response.0thanks for the advice everyone, you all have been great so you have a nice day

pwnzerer
 one year ago
Best ResponseYou've already chosen the best response.1YOU HAVE TO USE SEQENCES EVERTHING ELSE IS WRONG!!!!!!!!!!!!!!

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.216t^2  25 = 0 t(16t  25) = 0 16t = 25 f = 25/16 = 1.6
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