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IBhardcore

  • 2 years ago

Graph the expression sec2 x - sec2 x sin2 x on your calculator. Determine what constant or single function is equivalent to the given expression.

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  1. cwrw238
    • 2 years ago
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    are the 2\s powers?

  2. IBhardcore
    • 2 years ago
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    I got it. Nevermind.

  3. cwrw238
    • 2 years ago
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    if so = sec^2 x( 1 - sin^x) 1- sin^2 x = cos^2 x so we have sec^2x * cos^2 x cos^2x = ------- cos^2 x

  4. cwrw238
    • 2 years ago
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    = 1

  5. cwrw238
    • 2 years ago
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    agreed?

  6. IBhardcore
    • 2 years ago
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    Yep

  7. yummydum
    • 2 years ago
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    \[\sec^2x-\sec^2x~\sin^2x\]\[\left({1\over\cos^2x}\right)-\left({1\over\cos^2x}\right)~\sin^2x\]\[\left({1\over\cos^2x}\right)-\left({\sin^2x\over\cos^2x}\right)\]\[~~{1-\sin^2x\over\cos^2x}\]\[~~~{\cos^2x\over\cos^2x}\]\[~~~=1\]

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