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cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
dw:1372535299105:dw
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
can you continue from here?
 one year ago

dontothabonbon Group TitleBest ResponseYou've already chosen the best response.0
Thanks. I'm not sure what to do from here.
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
tan x = opposite / adjacent = 1 / sqrt15 sec x = hypotenuse / adjacent = ?
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.1
http://faculty.wlc.edu/buelow/PRC/T2_1.jpg
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.1
dw:1372535888225:dw
 one year ago

dontothabonbon Group TitleBest ResponseYou've already chosen the best response.0
Alright now I see. Thanks to both of you.
 one year ago

dontothabonbon Group TitleBest ResponseYou've already chosen the best response.0
Would the hypotenuse become a negative when calculating sec? Or would it just be: sec x = 4/sqrt15?
 one year ago

dontothabonbon Group TitleBest ResponseYou've already chosen the best response.0
Or better yet, why did the 1 become negative when calculating the tangent?
 one year ago

Jhannybean Group TitleBest ResponseYou've already chosen the best response.0
Because your function is in the second quadrant where sine is positive and cosine is negative.
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
the whole ratio became negative tangent : opposite = 1 , adjacent =  sqrt15 tan = 1 / sqrt15 = 1/sqrt15
 one year ago

Jhannybean Group TitleBest ResponseYou've already chosen the best response.0
\[\large \left(\frac{1}{\sqrt{15}}\right)\]
 one year ago

dontothabonbon Group TitleBest ResponseYou've already chosen the best response.0
So, sec = 4/sqrt15?
 one year ago

dontothabonbon Group TitleBest ResponseYou've already chosen the best response.0
ahh okay I see now thanks.
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
x values to the left of yaxis are negative y values below x axis are also negative
 one year ago
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