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What part of this is giving you trouble?

when i try to substitute the f(x) to the 3[f(2x)] i can't get the answer

You substitute 2x into f(x), then multiply through the whole thing by 3.

Hmmm... and yes, if that is written right, I can see why that would not get an answer.

Is it supposed to be \(3[f(2)]\)?? Rather than 2x?

the answer is 108x^2 + 9/2?

its 2x

Yes, as written, \(108x^2 + \cfrac{9}{2}\) would be correct.

if u want this answer then u should in question (3x)^2 instead of 3(x^2)

Ah, yes... I see what Muhammad_Nauman_Umair is pointing out.

thanks for your help guys @Muhammad_Nauman_Umair and @e.mccormick

\(36x^2 + \cfrac{9}{2}\) is what it should be.

36x^2+9/2