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RupaBoseBest ResponseYou've already chosen the best response.0
\[\int\limits\limits{6(\cos^3 (3x)) dx}=6\int\limits\limits{(\cos^2(3x)*\cos(3x) dx}=6\int\limits\limits{(1\sin^2(3x))(\cos (3x) dx}=6\int\limits\limits{\cos(3x)\sin^2(3x)\cos(3x) dx}=6[\frac{ \sin(3x) }{ 3 } \int\limits{\sin^2(3x)\cos(3x) dx]=2\sin (3x)6[\frac{\sin^3(3x)}{9}]+C=2\sin(3x)+\frac{2}{3}\sin^2(3x)+C}\]
 9 months ago

RupaBoseBest ResponseYou've already chosen the best response.0
\[\int\limits\limits\limits{6(\cos^3 (3x)) dx}=6\int\limits\limits\limits{(\cos^2(3x)*\cos(3x) dx}\] \[=6\int\limits\limits\limits\limits\limits{(1\sin^2(3x))(\cos (3x) dx}\] \[=6\int\limits\limits\limits{\cos(3x)\sin^2(3x)\cos(3x) dx}\] \[=6[\frac{ \sin(3x) }{ 3 } \int\limits\limits{\sin^2(3x)\cos(3x) dx]}\] \[=2\sin (3x)6[\frac{\sin^3(3x)}{9}]+C\] \[=2\sin(3x)+\frac{2}{3}\sin^2(3x)+C\]
 9 months ago

MrWhoBest ResponseYou've already chosen the best response.0
If you couldn't find the integration just use the online integration solver and see the solution to have full grasp of the integration techniques.
 8 months ago

sashankvillaBest ResponseYou've already chosen the best response.0
2⋅(sin(3x)−(sin(3x))^3/3)
 7 months ago
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