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RupaBose Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits\limits{6(\cos^3 (3x)) dx}=6\int\limits\limits{(\cos^2(3x)*\cos(3x) dx}=6\int\limits\limits{(1\sin^2(3x))(\cos (3x) dx}=6\int\limits\limits{\cos(3x)\sin^2(3x)\cos(3x) dx}=6[\frac{ \sin(3x) }{ 3 } \int\limits{\sin^2(3x)\cos(3x) dx]=2\sin (3x)6[\frac{\sin^3(3x)}{9}]+C=2\sin(3x)+\frac{2}{3}\sin^2(3x)+C}\]
 one year ago

RupaBose Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits\limits\limits{6(\cos^3 (3x)) dx}=6\int\limits\limits\limits{(\cos^2(3x)*\cos(3x) dx}\] \[=6\int\limits\limits\limits\limits\limits{(1\sin^2(3x))(\cos (3x) dx}\] \[=6\int\limits\limits\limits{\cos(3x)\sin^2(3x)\cos(3x) dx}\] \[=6[\frac{ \sin(3x) }{ 3 } \int\limits\limits{\sin^2(3x)\cos(3x) dx]}\] \[=2\sin (3x)6[\frac{\sin^3(3x)}{9}]+C\] \[=2\sin(3x)+\frac{2}{3}\sin^2(3x)+C\]
 one year ago

MrWho Group TitleBest ResponseYou've already chosen the best response.0
If you couldn't find the integration just use the online integration solver and see the solution to have full grasp of the integration techniques.
 one year ago

sashankvilla Group TitleBest ResponseYou've already chosen the best response.0
2⋅(sin(3x)−(sin(3x))^3/3)
 one year ago
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