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alienshe
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I'm trying to find the inverse of an equation and I'm not sure what to do next. http://oi43.tinypic.com/xldkhu.jpg
 one year ago
 one year ago
alienshe Group Title
I'm trying to find the inverse of an equation and I'm not sure what to do next. http://oi43.tinypic.com/xldkhu.jpg
 one year ago
 one year ago

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hartnn Group TitleBest ResponseYou've already chosen the best response.1
how u got x= 3ln y ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
f(x) = 3+ ln x y= 3+ ln x interchange 'x' and 'y' x = 3+ ln y can u try to isolate 'y' from here ?
 one year ago

alienshe Group TitleBest ResponseYou've already chosen the best response.1
(I'm just a tard who makes mistakes too often on her math homework...) Right now I have x3=lny.
 one year ago

alienshe Group TitleBest ResponseYou've already chosen the best response.1
Not sure what to do now
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
you are correct till that step! now use this : \(\large a= \ln b \implies e^a = b\) from the definition , so what about (x3) = ln y ?
 one year ago

alienshe Group TitleBest ResponseYou've already chosen the best response.1
\[y=e ^{x3}\]
 one year ago

alienshe Group TitleBest ResponseYou've already chosen the best response.1
Is that the right answer?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
absolutely! thats your inverse function :)
 one year ago

alienshe Group TitleBest ResponseYou've already chosen the best response.1
Thanks for the help! :)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
welcome ^_^
 one year ago
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