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itsonlycdeee
 one year ago
Prove the identity.
sec θ − cos(−θ) = sin^2θ/cosθ
I'm trying to transform the left side to the right side & so far I got:
1/ cosθ  cos(θ) =
1/cosθ  cosθ =
itsonlycdeee
 one year ago
Prove the identity. sec θ − cos(−θ) = sin^2θ/cosθ I'm trying to transform the left side to the right side & so far I got: 1/ cosθ  cos(θ) = 1/cosθ  cosθ =

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cwrw238
 one year ago
Best ResponseYou've already chosen the best response.1sin^2θ/cosθ = (1  cos^2θ)/cosθ = 1 / cosθ  cos θ = secθ  cos θ

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1if you want to continue from where you have left, try to make a common denominator \(\dfrac{1}{\cos \theta} \cos \theta \times \dfrac{\cos \theta}{\cos \theta}=\dfrac{1\cos^2 \theta}{\cos \theta}\) and lastly the use of \(\sin^2 x+\cos^2 x=1\) will lead you to right side :)

itsonlycdeee
 one year ago
Best ResponseYou've already chosen the best response.1@hartnm okay, that's what I'm attempting right now.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1good, did you get what i did ? if yes, can you continue ?

itsonlycdeee
 one year ago
Best ResponseYou've already chosen the best response.1Yes, it becomes sin^2θ/ cosθ. Thank you so much!

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1you're most welcome ^_^

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.1with these problems its often easier to start with the more complicated side as i did here

itsonlycdeee
 one year ago
Best ResponseYou've already chosen the best response.1@cwrw238 yeah, it'd take a few steps longer to go from the simpler side to the difficult one.
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