Stats :
From a deck of 52 cards,a card is drawn at random.Find the probability that it is:
A) a red card B) a face card C)a diamond card D) either a ten,or a queen E) a face card,or a 5,or a 4 of spade.

- uri

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- uri

What? How?

- anonymous

no of card by total cards i hope....

- hartnn

yes, first find how many red cards are there in total
then divide it by total number of cards
P =#red cards / total # of cards

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## More answers

- anonymous

imean .. as first one ... no of red cards / total no of cards ...

- anonymous

no of face card by total no of cards ;....

- uri

How to find how many red cards are there?

- hartnn

if you know what a deck is,
you will know how many red and black cards are there
and how many face cards also

- anonymous

got to know the chart ..... if u play card ....

- uri

-____________- I don't know? playing cards is HARAM.

- hartnn

http://en.wikipedia.org/wiki/Standard_52-card_deck

- anonymous

hmm ... neither mee but for doing the sum gota know the chart ...

- hartnn

red cards = diamond cards + heart cards

- uri

@hartnn So there are always 13 red cards,hartnn? so 13/52?

- hartnn

there are 13 heart cards and 13 diamond cards
both are considered as red
so, total # of red cards = 26
P= 26/52=....?

- uri

Wait 13 diamond,13 hearts so 26?

- anonymous

hope 26/52

- uri

Lol yes got it. @hartnn

- uri

so 26/52 =0.5

- hartnn

yes, 0.5 is correct :)
Face cards - Jacks, Queens, and Kings are called "face cards" because the cards have pictures of their names.
so, in 52, how many face cards will be there ?

- hartnn

note: there are total 4jacks, 4 queens and 4 kings, one of each suit.

- uri

12/52

- uri

@hartnn

- hartnn

12/52 is correct.
how are face cards 36 in number ?

- uri

yay so 0.230769

- anonymous

kk calculated ace too...

- hartnn

C. is simple total 13 diamonds
P=... ?

- uri

13/52

- hartnn

yes, correct
d) there are 4 tens one of each suit
same way, there are 4 queens , one of each suit
P=....?

- hartnn

'or' means addition

- uri

0.25 for diamond cards,and what does *one on each suit* means?

- hartnn

there are 4 suits in the deck
hearts
spades
diamonds
and clubs

- hartnn

look at the wiki link for details

- hartnn

so, 4 tens are
1 ten of heart
1 ten of spade
1 ten of diamond
and 1 ten of club
same for every other card!

- hartnn

can you get d) now ?

- uri

Okay so i have a choice i can either go for *a ten* or a *queen* I go for queen so,4/52 = 0.0769

- hartnn

'or' in probability means we add the individual probabilities
4/52 for queen + 4/52 for a ten
(4+4)/52 will be final answer for d)...just simplify

- uri

Oh then that concept is confusing but okay *8/52?*

- uri

0.15384

- hartnn

yes, 8/52 ...simplify that.
same for last part
just add total number of face cards + total # of 5's and total # of 4 of spade

- uri

Face cards are 12,total 5's are 4 and spade's are 4? So,12+4+4 =20/52 =0.3846153.

- hartnn

there are total 4 4's
one 4 of heart,
one 4 of diamonds
one 4 of spades
and one 4 of clubs

- hartnn

so how many # of 4 of spades ?

- uri

Huh? o_O 4?

- hartnn

Face cards are 12,total 5's are 4 <---correct
there is only \(\huge 1\) 4 of spade

- uri

*A 4 of spades?* so only 1 spade? :p

- hartnn

there are total 4 4's
one 4 of heart,
one 4 of diamonds
one 4 of spades <------here , only 1
and one 4 of clubs
in the question "4 of spade" is asked, which is unique
in all there are 13 spades

- uri

Don't understand :p

- hartnn

which part ?
only '4 of spade' ?
because # of faces=12 .....correct.
# of 5's =4 ....correct (one of each suit)
# of 4 of spade =.... ?

- uri

I don't understand # of 4 of spade

- hartnn

ok,
there are 13 cards in each suit
A,2,3,4......9,10, J, Q, K
A,2,3,4......9,10, J, Q, K of hearts
A,2,3,4......9,10, J, Q, K of diamonds
A,2,3,4......9,10, J, Q, K of spades
A,2,3,4......9,10, J, Q, K of clubs
total =52
out of this, how many '4' of spades are there ?

- Jack1

there's 1x ace of spades in a deck
1x 2 of spades
1x 3 of spades
1x 4 of spades ######## <----
1x 5 of spades... etc

- hartnn

https://upload.wikimedia.org/wikipedia/commons/thumb/2/2c/Playing_card_spade_4.svg/200px-Playing_card_spade_4.svg.png

- Jack1

how many of this card are there in a deck...?

##### 1 Attachment

- Jack1

EXACTLY that card...

- hartnn

^ only \(\huge \color {red}1\) 4 of spade, unique!

- uri

Okay so there are always 13 spades...? :3

- hartnn

yes, total 13 spades
but that info you don't need here

- hartnn

E) a face card,or a 5,or a 4 of spade.
a face ---->12
a 5----->4
a 4 of spade --->1
P=(12+4+1)/52

- uri

Okay...:) So i have a Question when there was *A face card* why we didn't use 1?

- hartnn

because there are in all 12 face cards
one Jack of heart
one Jack of diamond
one Jack of club
one Jack of spade
total 4 jacks
similarly, 4 queens and 4 kings
total face cards = 12

- uri

Oh...:D so aren't spades 13 in total? :P

- hartnn

yes, there are 13 spades in all
A,2,3,4......9,10, J, Q, K of spades <-----total =13
what made you ask this ?

- uri

WHY ARE WE USING 1 THEN!! THAT MADE ME ASK.. :3

- whpalmer4

1 = A

- hartnn

because the question doesn't ask of only spades
only spades = 13
its ask for a "4 of spade"
which is unique

- uri

Okay :P so we use *1?* so face cards is 12,5's are 4 so 12+4+1/52 =17/52 =0.32692

- hartnn

https://encrypted-tbn3.gstatic.com/images?q=tbn:ANd9GcT-kzBGpMtaZYdLHrZ6Q2cyk9CyLyEvXysGlomM6aXTGfi3xql1Lw
yes.

- hartnn

if thats blurred
http://www.geeksforgeeks.org/wp-content/uploads/cards.png

- uri

Aren't you smart? :3

- hartnn

O.o
is that a part of the question ?
(answer : P=1 :P)

- uri

P =1? answer of what? :3

- hartnn

of 'Aren't you smart?'
nvm if you didn't get it.......

- Jack1

lol

- uri

So you mean you are *A 4 of spade smart*? :P

- Jack1

probability = 100%

- terenzreignz

Drawing a single card? Boring... :P

- uri

Ha! Thanks @hartnn Bhaiya :D

- hartnn

always welcome ^_^

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