How would I find the domain and range of (2)/(x^2-2x-3)? Is the domain x=-1 x=3
Stacey Warren - Expert brainly.com
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try factoring the denominator
what values of x are not possible?
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so -1 and 3 are not in the domain
The domain is the values that x can have.
y = 2/(x^2 - 2x - 3)
has a denominator. Since division by zero is not allowed, you need to find which values of x would make the denominator zero. To do that, solve (which you did)
x^2 - 2x - 3 = 0
(x - 3)(x + 1) = 0
x = 3 or x = -1
These are the value of x that must be excluded from the domain, so the domain is all real numbers except x = 3 and x = -1.
oh so all reals except x=-1 and x=3 for the domain
ok thanks! but what about the range?
the range is all possible values of f(x)
so can you figure that out?
um how would i set it up?
dang ok.. don't solve it for me but how would i go about that?
well for a start the values of f(x) corresponding to x=3 or -1 will be excluded
Couldn't I find the inverse of the function and then find the domain?
yes the inverse of the function has domain which equals range of the function