anonymous
  • anonymous
How would I find the domain and range of (2)/(x^2-2x-3)? Is the domain x=-1 x=3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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cwrw238
  • cwrw238
try factoring the denominator what values of x are not possible?
anonymous
  • anonymous
x=-1 and x=3
cwrw238
  • cwrw238
the domain is all possible values of x

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cwrw238
  • cwrw238
right
cwrw238
  • cwrw238
so -1 and 3 are not in the domain
mathstudent55
  • mathstudent55
The domain is the values that x can have. y = 2/(x^2 - 2x - 3) has a denominator. Since division by zero is not allowed, you need to find which values of x would make the denominator zero. To do that, solve (which you did) x^2 - 2x - 3 = 0 (x - 3)(x + 1) = 0 x = 3 or x = -1 These are the value of x that must be excluded from the domain, so the domain is all real numbers except x = 3 and x = -1.
anonymous
  • anonymous
oh so all reals except x=-1 and x=3 for the domain
cwrw238
  • cwrw238
yup
anonymous
  • anonymous
ok thanks! but what about the range?
cwrw238
  • cwrw238
the range is all possible values of f(x)
cwrw238
  • cwrw238
so can you figure that out?
anonymous
  • anonymous
um how would i set it up?
anonymous
  • anonymous
dang ok.. don't solve it for me but how would i go about that?
cwrw238
  • cwrw238
well for a start the values of f(x) corresponding to x=3 or -1 will be excluded
anonymous
  • anonymous
Couldn't I find the inverse of the function and then find the domain?
anonymous
  • anonymous
@cwrw238
cwrw238
  • cwrw238
yes the inverse of the function has domain which equals range of the function
anonymous
  • anonymous
ok thanks for your time and patience!
cwrw238
  • cwrw238
yw

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