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no0zer

  • 2 years ago

A stone of mass 0.55 kilograms is released and falls to the ground. Measurements show that the stone has a kinetic energy of 9.8 joules at the point of impact with the ground. What is the stone's velocity when it hits the ground?

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  1. Shane_B
    • 2 years ago
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    \[KE=\frac{1}{2}mv^2\]\[9.8J=\frac{1}{2}(0.55kg)v^2\]Solve for v.

  2. no0zer
    • 2 years ago
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    thx :)

  3. Shane_B
    • 2 years ago
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    np :)

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