Here's the question you clicked on:
no0zer
A stone of mass 0.55 kilograms is released and falls to the ground. Measurements show that the stone has a kinetic energy of 9.8 joules at the point of impact with the ground. What is the stone's velocity when it hits the ground?
\[KE=\frac{1}{2}mv^2\]\[9.8J=\frac{1}{2}(0.55kg)v^2\]Solve for v.