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SNIIX18
 one year ago
Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum?
A. 13 seconds
B. 1.3 seconds
C. 3.5 seconds
D. 0.76 seconds
SNIIX18
 one year ago
Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum? A. 13 seconds B. 1.3 seconds C. 3.5 seconds D. 0.76 seconds

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theEric
 one year ago
Best ResponseYou've already chosen the best response.1That link backs up souvik's response. It might also help you find other information.

SNIIX18
 one year ago
Best ResponseYou've already chosen the best response.0Thank you both :) @theEric that link was very helpful Grazie

theEric
 one year ago
Best ResponseYou've already chosen the best response.1You're welcome! And I guess that equation only works for a "simple pendulum."

SNIIX18
 one year ago
Best ResponseYou've already chosen the best response.0yahh i cant wrap my finger around this problem its kind of difficult

SNIIX18
 one year ago
Best ResponseYou've already chosen the best response.0yes it's kind of difficult for me

SNIIX18
 one year ago
Best ResponseYou've already chosen the best response.0i just dont understand

souvik
 one year ago
Best ResponseYou've already chosen the best response.1i divide the force mg into two component one is mgcos(theta) and mssin(theta) any question?

SNIIX18
 one year ago
Best ResponseYou've already chosen the best response.0no i understand know i was doing everything wrong Thank you for the help
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