## SNIIX18 Group Title Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum? A. 13 seconds B. 1.3 seconds C. 3.5 seconds D. 0.76 seconds one year ago one year ago

1. souvik Group Title

$T=2\pi \sqrt{L/g}$

2. theEric Group Title
3. theEric Group Title

That link backs up souvik's response. It might also help you find other information.

4. SNIIX18 Group Title

Thank you both :) @theEric that link was very helpful Grazie

5. theEric Group Title

You're welcome! And I guess that equation only works for a "simple pendulum."

6. souvik Group Title

any problem? @SNIIX18

7. SNIIX18 Group Title

yahh i cant wrap my finger around this problem its kind of difficult

8. souvik Group Title

this question?

9. SNIIX18 Group Title

yes it's kind of difficult for me

10. souvik Group Title

what happened?

11. SNIIX18 Group Title

i just dont understand

12. souvik Group Title

|dw:1372793064271:dw|

13. souvik Group Title

|dw:1372793264146:dw|

14. souvik Group Title

i divide the force mg into two component one is mgcos(theta) and mssin(theta) any question?

15. SNIIX18 Group Title

no i understand know i was doing everything wrong Thank you for the help

16. souvik Group Title

ok....