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anonymous
 3 years ago
Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum?
A. 13 seconds
B. 1.3 seconds
C. 3.5 seconds
D. 0.76 seconds
anonymous
 3 years ago
Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum? A. 13 seconds B. 1.3 seconds C. 3.5 seconds D. 0.76 seconds

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theEric
 3 years ago
Best ResponseYou've already chosen the best response.1That link backs up souvik's response. It might also help you find other information.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you both :) @theEric that link was very helpful Grazie

theEric
 3 years ago
Best ResponseYou've already chosen the best response.1You're welcome! And I guess that equation only works for a "simple pendulum."

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yahh i cant wrap my finger around this problem its kind of difficult

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes it's kind of difficult for me

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i just dont understand

souvik
 3 years ago
Best ResponseYou've already chosen the best response.1i divide the force mg into two component one is mgcos(theta) and mssin(theta) any question?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no i understand know i was doing everything wrong Thank you for the help
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