SNIIX18
Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum?
A. 13 seconds
B. 1.3 seconds
C. 3.5 seconds
D. 0.76 seconds
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souvik
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\[T=2\pi \sqrt{L/g}\]
theEric
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That link backs up souvik's response. It might also help you find other information.
SNIIX18
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Thank you both :) @theEric that link was very helpful Grazie
theEric
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You're welcome! And I guess that equation only works for a "simple pendulum."
souvik
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any problem? @SNIIX18
SNIIX18
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yahh i cant wrap my finger around this problem its kind of difficult
souvik
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this question?
SNIIX18
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yes it's kind of difficult for me
souvik
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what happened?
SNIIX18
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i just dont understand
souvik
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|dw:1372793064271:dw|
souvik
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|dw:1372793264146:dw|
souvik
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i divide the force mg into two component one is mgcos(theta) and mssin(theta)
any question?
SNIIX18
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no i understand know i was doing everything wrong Thank you for the help
souvik
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ok....