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SNIIX18
Group Title
Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum?
A. 13 seconds
B. 1.3 seconds
C. 3.5 seconds
D. 0.76 seconds
 one year ago
 one year ago
SNIIX18 Group Title
Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum? A. 13 seconds B. 1.3 seconds C. 3.5 seconds D. 0.76 seconds
 one year ago
 one year ago

This Question is Closed

souvik Group TitleBest ResponseYou've already chosen the best response.1
\[T=2\pi \sqrt{L/g}\]
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
http://hyperphysics.phyastr.gsu.edu/hbase/pend.html
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
That link backs up souvik's response. It might also help you find other information.
 one year ago

SNIIX18 Group TitleBest ResponseYou've already chosen the best response.0
Thank you both :) @theEric that link was very helpful Grazie
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
You're welcome! And I guess that equation only works for a "simple pendulum."
 one year ago

souvik Group TitleBest ResponseYou've already chosen the best response.1
any problem? @SNIIX18
 one year ago

SNIIX18 Group TitleBest ResponseYou've already chosen the best response.0
yahh i cant wrap my finger around this problem its kind of difficult
 one year ago

souvik Group TitleBest ResponseYou've already chosen the best response.1
this question?
 one year ago

SNIIX18 Group TitleBest ResponseYou've already chosen the best response.0
yes it's kind of difficult for me
 one year ago

souvik Group TitleBest ResponseYou've already chosen the best response.1
what happened?
 one year ago

SNIIX18 Group TitleBest ResponseYou've already chosen the best response.0
i just dont understand
 one year ago

souvik Group TitleBest ResponseYou've already chosen the best response.1
dw:1372793064271:dw
 one year ago

souvik Group TitleBest ResponseYou've already chosen the best response.1
dw:1372793264146:dw
 one year ago

souvik Group TitleBest ResponseYou've already chosen the best response.1
i divide the force mg into two component one is mgcos(theta) and mssin(theta) any question?
 one year ago

SNIIX18 Group TitleBest ResponseYou've already chosen the best response.0
no i understand know i was doing everything wrong Thank you for the help
 one year ago
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