anonymous
  • anonymous
Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/secondĀ², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum? A. 13 seconds B. 1.3 seconds C. 3.5 seconds D. 0.76 seconds
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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souvik
  • souvik
\[T=2\pi \sqrt{L/g}\]
theEric
  • theEric
http://hyperphysics.phy-astr.gsu.edu/hbase/pend.html
theEric
  • theEric
That link backs up souvik's response. It might also help you find other information.

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anonymous
  • anonymous
Thank you both :) @theEric that link was very helpful Grazie
theEric
  • theEric
You're welcome! And I guess that equation only works for a "simple pendulum."
souvik
  • souvik
any problem? @SNIIX18
anonymous
  • anonymous
yahh i cant wrap my finger around this problem its kind of difficult
souvik
  • souvik
this question?
anonymous
  • anonymous
yes it's kind of difficult for me
souvik
  • souvik
what happened?
anonymous
  • anonymous
i just dont understand
souvik
  • souvik
|dw:1372793064271:dw|
souvik
  • souvik
|dw:1372793264146:dw|
souvik
  • souvik
i divide the force mg into two component one is mgcos(theta) and mssin(theta) any question?
anonymous
  • anonymous
no i understand know i was doing everything wrong Thank you for the help
souvik
  • souvik
ok....

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