## SNIIX18 2 years ago Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum? A. 13 seconds B. 1.3 seconds C. 3.5 seconds D. 0.76 seconds

1. souvik

$T=2\pi \sqrt{L/g}$

2. theEric
3. theEric

4. SNIIX18

5. theEric

You're welcome! And I guess that equation only works for a "simple pendulum."

6. souvik

any problem? @SNIIX18

7. SNIIX18

yahh i cant wrap my finger around this problem its kind of difficult

8. souvik

this question?

9. SNIIX18

yes it's kind of difficult for me

10. souvik

what happened?

11. SNIIX18

i just dont understand

12. souvik

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13. souvik

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14. souvik

i divide the force mg into two component one is mgcos(theta) and mssin(theta) any question?

15. SNIIX18

no i understand know i was doing everything wrong Thank you for the help

16. souvik

ok....