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Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/secondĀ², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum? A. 13 seconds B. 1.3 seconds C. 3.5 seconds D. 0.76 seconds

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\[T=2\pi \sqrt{L/g}\]
That link backs up souvik's response. It might also help you find other information.

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Other answers:

Thank you both :) @theEric that link was very helpful Grazie
You're welcome! And I guess that equation only works for a "simple pendulum."
any problem? @SNIIX18
yahh i cant wrap my finger around this problem its kind of difficult
this question?
yes it's kind of difficult for me
what happened?
i just dont understand
i divide the force mg into two component one is mgcos(theta) and mssin(theta) any question?
no i understand know i was doing everything wrong Thank you for the help

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