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anonymous 3 years ago Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum? A. 13 seconds B. 1.3 seconds C. 3.5 seconds D. 0.76 seconds

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1. souvik

$T=2\pi \sqrt{L/g}$

2. theEric
3. theEric

That link backs up souvik's response. It might also help you find other information.

4. anonymous

Thank you both :) @theEric that link was very helpful Grazie

5. theEric

You're welcome! And I guess that equation only works for a "simple pendulum."

6. souvik

any problem? @SNIIX18

7. anonymous

yahh i cant wrap my finger around this problem its kind of difficult

8. souvik

this question?

9. anonymous

yes it's kind of difficult for me

10. souvik

what happened?

11. anonymous

i just dont understand

12. souvik

|dw:1372793064271:dw|

13. souvik

|dw:1372793264146:dw|

14. souvik

i divide the force mg into two component one is mgcos(theta) and mssin(theta) any question?

15. anonymous

no i understand know i was doing everything wrong Thank you for the help

16. souvik

ok....

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