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anonymous
 2 years ago
I am asked to solve 42=x^2x
How do I solve this?
anonymous
 2 years ago
I am asked to solve 42=x^2x How do I solve this?

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johnweldon1993
 2 years ago
Best ResponseYou've already chosen the best response.0Notice how if you subtract 42 from both sides you get \[x^2  x  42 = 0\] Does that look like something familiar?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So in order to solve this, you need to set the right side equal to 0 by subtracting 42. \[x ^{2}x42\] Next you need to factor this. The factors of 42 that equal 1 are 6 and 7, so (x+6)(x7)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Got it thanks for the help

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0You're very welcome :)
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