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noname81
 one year ago
I am asked to solve 42=x^2x
How do I solve this?
noname81
 one year ago
I am asked to solve 42=x^2x How do I solve this?

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johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Notice how if you subtract 42 from both sides you get \[x^2  x  42 = 0\] Does that look like something familiar?

celecity
 one year ago
Best ResponseYou've already chosen the best response.1So in order to solve this, you need to set the right side equal to 0 by subtracting 42. \[x ^{2}x42\] Next you need to factor this. The factors of 42 that equal 1 are 6 and 7, so (x+6)(x7)

noname81
 one year ago
Best ResponseYou've already chosen the best response.0Got it thanks for the help

celecity
 one year ago
Best ResponseYou've already chosen the best response.1You're very welcome :)
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