A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
noname81
 2 years ago
I am asked to solve 42=x^2x
How do I solve this?
noname81
 2 years ago
I am asked to solve 42=x^2x How do I solve this?

This Question is Closed

johnweldon1993
 2 years ago
Best ResponseYou've already chosen the best response.0Notice how if you subtract 42 from both sides you get \[x^2  x  42 = 0\] Does that look like something familiar?

celecity
 2 years ago
Best ResponseYou've already chosen the best response.1So in order to solve this, you need to set the right side equal to 0 by subtracting 42. \[x ^{2}x42\] Next you need to factor this. The factors of 42 that equal 1 are 6 and 7, so (x+6)(x7)

noname81
 2 years ago
Best ResponseYou've already chosen the best response.0Got it thanks for the help

celecity
 2 years ago
Best ResponseYou've already chosen the best response.1You're very welcome :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.