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noname81

  • one year ago

I am asked to solve 42=x^2-x How do I solve this?

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  1. johnweldon1993
    • one year ago
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    Notice how if you subtract 42 from both sides you get \[x^2 - x - 42 = 0\] Does that look like something familiar?

  2. celecity
    • one year ago
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    So in order to solve this, you need to set the right side equal to 0 by subtracting 42. \[x ^{2}-x-42\] Next you need to factor this. The factors of -42 that equal -1 are 6 and -7, so (x+6)(x-7)

  3. celecity
    • one year ago
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    *\[x ^{2}-x-42=0\]

  4. noname81
    • one year ago
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    Got it thanks for the help

  5. celecity
    • one year ago
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    You're very welcome :)

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