Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

noname81

  • 2 years ago

I am asked to solve 42=x^2-x How do I solve this?

  • This Question is Closed
  1. johnweldon1993
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Notice how if you subtract 42 from both sides you get \[x^2 - x - 42 = 0\] Does that look like something familiar?

  2. celecity
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    So in order to solve this, you need to set the right side equal to 0 by subtracting 42. \[x ^{2}-x-42\] Next you need to factor this. The factors of -42 that equal -1 are 6 and -7, so (x+6)(x-7)

  3. celecity
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    *\[x ^{2}-x-42=0\]

  4. noname81
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Got it thanks for the help

  5. celecity
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You're very welcome :)

  6. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy