Andrea's change purse contained 8 quarters, 9 dimes, and 8 nickels.If andrea chose 2 coins randomly without replacing them in her purse,what is the probability that she chose 2 dimes?

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Andrea's change purse contained 8 quarters, 9 dimes, and 8 nickels.If andrea chose 2 coins randomly without replacing them in her purse,what is the probability that she chose 2 dimes?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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flutter you
uhm, excuse me. but can i get an explanation on this problem,please really stuck on this.
ok so we have 25 coins altogether

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and we have 9 dimes
okay im following
So the first time we choose a coin the probability that it will be a dime is 9/25 correct?
Yeah?
ya there are 25 coins altogether and 9 dimes so the probability that it will be a dime is dimes/total amt of coins = 9/25
The second time we choose a coin
okay i get you
there are only 24 coins left cuz we picked a dime
okay
so there are 24 coins and 8 dimes so the probabiity we will choose a dime is 8/24
So altogether the probability that we will choose 2 dimes is 9/25*8/24
so the answer would be 3/25, right?
yup :)
Omg! Thank You So Much!(:

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