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Brutus.
 2 years ago
Need some Assistance. (x3)^2/(x+1)(x2)>0
I'm supposed to solve it and express my answer in interval notation.
Brutus.
 2 years ago
Need some Assistance. (x3)^2/(x+1)(x2)>0 I'm supposed to solve it and express my answer in interval notation.

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RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1372837027496:dw

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1is this \[\frac{(x3)^{2}}{(x+1)(x2)}\]?

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0Yes. that is the equation.

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1ok so the top is >0 for all x does not equal 3 right?

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1so we need to make sure the bottom is > 0 right?

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1372837247856:dw

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.0i have forgot 3

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1the bottom is a parabola that opens up, what are its x intercepts?

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1so the bottom is greater than 0 when x<1 and x>2, because it opens up and crosses y=0 at 1,2 with me?

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1so we know the top is grater than 0 when x is not 3 we know the bottom is greater than 0 when x<1 and x>2 so the whole thing is greater than 0 when x<1 and x>2 and x does not equal 3

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1(infinity,1)U(2,3)U(3,infinity)

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0I have another quick question

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0I had another problem like this and I solved it and got x<1. How would I write that in interval notation?

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1if it was <= (infinity,1]

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0The original problem was \[3(1\frac{ 3 }{4 }x)>5\frac{ 1 }{ 4 }x\]

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.13(9/4)x>5(1/4)x (8/4)x>53 2x<2 x<1 correct

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0\[x <1\] I wrote the interval notation like so (infinity,1). But for some reason, my professor marked off points and circled interval notation.

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1you sure it didn't say set builder?

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0The question said Solve the inequalities and express your answer in Interval notation.

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1he/she is wrong http://www.regentsprep.org/Regents/math/ALGEBRA/AP1/IntervalNot.htm look at non ending interval note: we have ) not ] because we have < not <=

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1just go talk to your teacher, I make mistakes grading all the time....

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{x=1 }{ 4}\ge4\]

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1is that plus or minus?

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0I know your supposed to get two answers. I got one which was \[x \ge15\]

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1ok so this is strange and you may need to think about it a bit, but when you have a=b we get a=b and a=b when you have a<b we get b<x<b when you have a>b we get a<b and a>b

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1the very last and should be or

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1*when you have a>b we get a<b or a>b

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0Okay, So if I want the other answer I set the 4 to a negative answer?

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1so you have abs((x+1)/4)>=4 so (x+1)/4>=4 gives the solutions you already have

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1now we do (x+1)/4<=4 x+1<=16 x<=17

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1set it negative and flip the sign

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0Ah, that's what confused me.. Didn't know what to do with my sign

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1you could have done (x+1)/4<=4 but as a rule I just make the "non absolute value side" negative

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0Good rule! With interval notation, how would I write this?

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0I think its \[(\infty,17]U(\infty,15]\]

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1(infinity,17]U[15,infinity)

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1think of the number line, write it in the order it would fall on the number line

zzr0ck3r
 2 years ago
Best ResponseYou've already chosen the best response.1and note that (infinity,5] does not make since, because if x were to be in there then infinity < x < 5

Brutus.
 2 years ago
Best ResponseYou've already chosen the best response.0But, Thank you so much for the help.
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