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Brutus.
 one year ago
Need some Assistance. (x3)^2/(x+1)(x2)>0
I'm supposed to solve it and express my answer in interval notation.
Brutus.
 one year ago
Need some Assistance. (x3)^2/(x+1)(x2)>0 I'm supposed to solve it and express my answer in interval notation.

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RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.0dw:1372837027496:dw

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1is this \[\frac{(x3)^{2}}{(x+1)(x2)}\]?

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0Yes. that is the equation.

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1ok so the top is >0 for all x does not equal 3 right?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1so we need to make sure the bottom is > 0 right?

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.0dw:1372837247856:dw

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.0i have forgot 3

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1the bottom is a parabola that opens up, what are its x intercepts?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1so the bottom is greater than 0 when x<1 and x>2, because it opens up and crosses y=0 at 1,2 with me?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1so we know the top is grater than 0 when x is not 3 we know the bottom is greater than 0 when x<1 and x>2 so the whole thing is greater than 0 when x<1 and x>2 and x does not equal 3

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1(infinity,1)U(2,3)U(3,infinity)

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0I have another quick question

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0I had another problem like this and I solved it and got x<1. How would I write that in interval notation?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1if it was <= (infinity,1]

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0The original problem was \[3(1\frac{ 3 }{4 }x)>5\frac{ 1 }{ 4 }x\]

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.13(9/4)x>5(1/4)x (8/4)x>53 2x<2 x<1 correct

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0\[x <1\] I wrote the interval notation like so (infinity,1). But for some reason, my professor marked off points and circled interval notation.

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1you sure it didn't say set builder?

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0The question said Solve the inequalities and express your answer in Interval notation.

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1he/she is wrong http://www.regentsprep.org/Regents/math/ALGEBRA/AP1/IntervalNot.htm look at non ending interval note: we have ) not ] because we have < not <=

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1just go talk to your teacher, I make mistakes grading all the time....

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{x=1 }{ 4}\ge4\]

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1is that plus or minus?

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0I know your supposed to get two answers. I got one which was \[x \ge15\]

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ x+1 }{4 }\]

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1ok so this is strange and you may need to think about it a bit, but when you have a=b we get a=b and a=b when you have a<b we get b<x<b when you have a>b we get a<b and a>b

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1the very last and should be or

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1*when you have a>b we get a<b or a>b

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0Okay, So if I want the other answer I set the 4 to a negative answer?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1so you have abs((x+1)/4)>=4 so (x+1)/4>=4 gives the solutions you already have

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1now we do (x+1)/4<=4 x+1<=16 x<=17

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1set it negative and flip the sign

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0Ah, that's what confused me.. Didn't know what to do with my sign

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1you could have done (x+1)/4<=4 but as a rule I just make the "non absolute value side" negative

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0Good rule! With interval notation, how would I write this?

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0I think its \[(\infty,17]U(\infty,15]\]

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1(infinity,17]U[15,infinity)

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1think of the number line, write it in the order it would fall on the number line

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1and note that (infinity,5] does not make since, because if x were to be in there then infinity < x < 5

Brutus.
 one year ago
Best ResponseYou've already chosen the best response.0But, Thank you so much for the help.
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