## kittycat01 Group Title differentiate tan^-1((a+btanx)/(b-atanx)) one year ago one year ago

1. hartnn

try and put b/a = tan (alpha) then (a+btanx)/(b-atanx) will be of the form tan (...+...)

2. kittycat01

oh

3. kittycat01

let me try by using ur method

4. kittycat01

@hartnn -:/

5. souvik

tan^-1{(a/b+tanx)/(1-a/btanx)} lets take $a/b=\tan \alpha$ tan^-1[{tan(alpha)+tanx}/1-tanx*tan(alpha)}] =tan^-1[tan(x+alpha) =x+alpha

6. hartnn

oh, it was a/b = tan alpha , not b/a :P

7. kittycat01

oh :OOO is there any other method to solve it ???????

8. kittycat01

i thought u can only substitute x variable only

9. hartnn

i feel this is the easiest :) here we replaced one constant, (a/b) with other ...

10. kittycat01

oh :O

11. kittycat01

@souvik @hartnn -why allpha not tanx ???????

12. kittycat01

alpha*

13. hartnn

tan x ? ''x'' is a variable, whereas a and b are constants we can replace a constant by a constant, and variable by a variable not a constant by a variable and....

14. kittycat01

oh :OOO