kittycat01
differentiate
tan^-1((a+btanx)/(b-atanx))
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hartnn
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try and put b/a = tan (alpha)
then
(a+btanx)/(b-atanx) will be of the form tan (...+...)
kittycat01
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oh
kittycat01
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let me try by using ur method
kittycat01
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@hartnn -:/
souvik
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tan^-1{(a/b+tanx)/(1-a/btanx)}
lets take \[a/b=\tan \alpha \]
tan^-1[{tan(alpha)+tanx}/1-tanx*tan(alpha)}]
=tan^-1[tan(x+alpha)
=x+alpha
hartnn
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oh, it was a/b = tan alpha , not b/a :P
kittycat01
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oh :OOO is there any other method to solve it ???????
kittycat01
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i thought u can only substitute x variable only
hartnn
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i feel this is the easiest :)
here we replaced one constant, (a/b) with other ...
kittycat01
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oh :O
kittycat01
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@souvik @hartnn -why allpha not tanx ???????
kittycat01
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alpha*
hartnn
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tan x ? ''x'' is a variable,
whereas a and b are constants
we can replace a constant by a constant, and variable by a variable
not a constant by a variable and....
kittycat01
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oh :OOO