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kittycat01

  • 2 years ago

differentiate tan^-1((a+btanx)/(b-atanx))

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  1. hartnn
    • 2 years ago
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    try and put b/a = tan (alpha) then (a+btanx)/(b-atanx) will be of the form tan (...+...)

  2. kittycat01
    • 2 years ago
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    oh

  3. kittycat01
    • 2 years ago
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    let me try by using ur method

  4. kittycat01
    • 2 years ago
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    @hartnn -:/

  5. souvik
    • 2 years ago
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    tan^-1{(a/b+tanx)/(1-a/btanx)} lets take \[a/b=\tan \alpha \] tan^-1[{tan(alpha)+tanx}/1-tanx*tan(alpha)}] =tan^-1[tan(x+alpha) =x+alpha

  6. hartnn
    • 2 years ago
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    oh, it was a/b = tan alpha , not b/a :P

  7. kittycat01
    • 2 years ago
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    oh :OOO is there any other method to solve it ???????

  8. kittycat01
    • 2 years ago
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    i thought u can only substitute x variable only

  9. hartnn
    • 2 years ago
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    i feel this is the easiest :) here we replaced one constant, (a/b) with other ...

  10. kittycat01
    • 2 years ago
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    oh :O

  11. kittycat01
    • 2 years ago
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    @souvik @hartnn -why allpha not tanx ???????

  12. kittycat01
    • 2 years ago
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    alpha*

  13. hartnn
    • 2 years ago
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    tan x ? ''x'' is a variable, whereas a and b are constants we can replace a constant by a constant, and variable by a variable not a constant by a variable and....

  14. kittycat01
    • 2 years ago
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    oh :OOO

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