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anonymous
 3 years ago
differentiate
tan^1((a+btanx)/(batanx))
anonymous
 3 years ago
differentiate tan^1((a+btanx)/(batanx))

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hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2try and put b/a = tan (alpha) then (a+btanx)/(batanx) will be of the form tan (...+...)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let me try by using ur method

souvik
 3 years ago
Best ResponseYou've already chosen the best response.1tan^1{(a/b+tanx)/(1a/btanx)} lets take \[a/b=\tan \alpha \] tan^1[{tan(alpha)+tanx}/1tanx*tan(alpha)}] =tan^1[tan(x+alpha) =x+alpha

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2oh, it was a/b = tan alpha , not b/a :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh :OOO is there any other method to solve it ???????

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i thought u can only substitute x variable only

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2i feel this is the easiest :) here we replaced one constant, (a/b) with other ...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@souvik @hartnn why allpha not tanx ???????

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2tan x ? ''x'' is a variable, whereas a and b are constants we can replace a constant by a constant, and variable by a variable not a constant by a variable and....
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