anonymous
  • anonymous
differentiate tan^-1((a+btanx)/(b-atanx))
Mathematics
katieb
  • katieb
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hartnn
  • hartnn
try and put b/a = tan (alpha) then (a+btanx)/(b-atanx) will be of the form tan (...+...)
anonymous
  • anonymous
oh
anonymous
  • anonymous
let me try by using ur method

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anonymous
  • anonymous
souvik
  • souvik
tan^-1{(a/b+tanx)/(1-a/btanx)} lets take \[a/b=\tan \alpha \] tan^-1[{tan(alpha)+tanx}/1-tanx*tan(alpha)}] =tan^-1[tan(x+alpha) =x+alpha
hartnn
  • hartnn
oh, it was a/b = tan alpha , not b/a :P
anonymous
  • anonymous
oh :OOO is there any other method to solve it ???????
anonymous
  • anonymous
i thought u can only substitute x variable only
hartnn
  • hartnn
i feel this is the easiest :) here we replaced one constant, (a/b) with other ...
anonymous
  • anonymous
oh :O
anonymous
  • anonymous
@souvik @hartnn -why allpha not tanx ???????
anonymous
  • anonymous
alpha*
hartnn
  • hartnn
tan x ? ''x'' is a variable, whereas a and b are constants we can replace a constant by a constant, and variable by a variable not a constant by a variable and....
anonymous
  • anonymous
oh :OOO

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