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differentiate tan^-1((a+btanx)/(b-atanx))

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try and put b/a = tan (alpha) then (a+btanx)/(b-atanx) will be of the form tan (...+...)
let me try by using ur method

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Other answers:

tan^-1{(a/b+tanx)/(1-a/btanx)} lets take \[a/b=\tan \alpha \] tan^-1[{tan(alpha)+tanx}/1-tanx*tan(alpha)}] =tan^-1[tan(x+alpha) =x+alpha
oh, it was a/b = tan alpha , not b/a :P
oh :OOO is there any other method to solve it ???????
i thought u can only substitute x variable only
i feel this is the easiest :) here we replaced one constant, (a/b) with other ...
oh :O
@souvik @hartnn -why allpha not tanx ???????
tan x ? ''x'' is a variable, whereas a and b are constants we can replace a constant by a constant, and variable by a variable not a constant by a variable and....
oh :OOO

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