kittycat01
tan^1[(√x+√a)/(1√(xa))]
differentiate it plz
m gtting 1/2(√x)
which is not correct answer is
1/[2(√x)(1+x)]



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hartnn
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same type of question with different substitution

kittycat01
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hmm i think i did something wrong let me do it again

kittycat01
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well u don't have to substitue :) @hartnn
i think i forgot to differentiate tan^1 (x)^1/2
i missed the tan^1 part

hartnn
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say, sqrt x= tan y
sqrt a = tan alpha
then , [(√x+√a)/(1√(xa))] =... ?

hartnn
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ohh..so now did u get it ?

kittycat01
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u have to use tan^1 x + tan^1 y formula
well not now

kittycat01
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trying again

kittycat01
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:'( not getting :'(

kittycat01
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how to differnatiate tan^1(x)^1/2

hartnn
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use chain rule, know about it ?

kittycat01
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no :'( that's the problem simple chain rule i know

kittycat01
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like this one sin(cos3x) but never did for inverse trign.........

kittycat01
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is the differenatition of tan^1(x)^1/2 is

kittycat01
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is =X
=1/(1+(x^1/2)^2 . 1/2*(x)^1/2 ????????

hartnn
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ok, derivative of tan^{1} x is 1/(1+x^2), right ??
for derivative of tan^{1} sqrt(x)
you do
1/(1+ [\sqrt x]^2) times deribative of sqrt x

kittycat01
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yep

kittycat01
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i think i have used chain rule _ is that a chain rule @hartnn

souvik
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you did it,,,kitty

hartnn
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didn't you get the answer then ?
yes, thats was chain rule only...

kittycat01
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lol i know everything but still do silly things _ @souvik

souvik
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it happens some time...

kittycat01
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@hartnn 
chain rule :O
so that's a chain rule

hartnn
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because what you wrote matches with your final answer...

kittycat01
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not some times everytime it happens

souvik
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keep your head cool....like MSD

kittycat01
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bcoz of calculation mistake i lost 3 marks in maths prob :'(
i did everything correct but in final answer i made a error in multiplication

kittycat01
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MSD??????

kittycat01
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@hartnn tahnx :)

hartnn
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hey, welcome anytime ^_^

kittycat01
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:)

souvik
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Indian cricket team captain...

kittycat01
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oh :OOO ms dhoni :OOO i don't like him lol

souvik
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why?

kittycat01
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reminds me of my frenemy :P