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same type of question with different substitution

hmm i think i did something wrong let me do it again

say, sqrt x= tan y
sqrt a = tan alpha
then , [(√x+√a)/(1-√(xa))] =... ?

ohh..so now did u get it ?

u have to use tan^-1 x + tan^-1 y formula
well not now

trying again

:'( not getting :'(

how to differnatiate tan^-1(x)^1/2

use chain rule, know about it ?

no :'( that's the problem simple chain rule i know

like this one sin(cos3x) but never did for inverse trign.........

is the differenatition of tan^-1(x)^1/2 is

is =X
=1/(1+(x^1/2)^2 . 1/2*(x)^-1/2 ????????

yep

you did it,,,kitty

didn't you get the answer then ?
yes, thats was chain rule only...

it happens some time...

because what you wrote matches with your final answer...

not some times everytime it happens

keep your head cool....like MSD

MSD??????

hey, welcome anytime ^_^

:)

Indian cricket team captain...

oh :OOO ms dhoni :OOO i don't like him lol

why?

reminds me of my frenemy :P