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kittycat01

  • one year ago

when u are having in this form then how to differentiate :) tan^-1(2^(x+1)/(1-4^x)) can i use substitution here ?

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  1. kittycat01
    • one year ago
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    i don't think so substitution will work

  2. hartnn
    • one year ago
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    substitute 2^x = tan y

  3. hartnn
    • one year ago
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    lol, why not ?

  4. hartnn
    • one year ago
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    do you know tan 2 theta formula ?

  5. kittycat01
    • one year ago
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    coz i have never did this type of question lol

  6. kittycat01
    • one year ago
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    yep :)

  7. kittycat01
    • one year ago
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    2tanα/(1 – tan²α)

  8. hartnn
    • one year ago
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    2^(x+1) = 2. 2^x , 4^x = (2^x)^2 plug in 2^x = tan y and see the magic! (simplification :P)

  9. kittycat01
    • one year ago
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    will it really works :PPPP lol i hate chain rule -_-

  10. kittycat01
    • one year ago
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    don't wanna use chain rule for inverse trig ...........

  11. hartnn
    • one year ago
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    ? what did you get after simplification ?

  12. hartnn
    • one year ago
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    i don't think chain rule is required here...

  13. kittycat01
    • one year ago
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    wait :))

  14. Abhishek619
    • one year ago
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    use tan(x+y)=(tanx+tany)/(1-tanxtany)

  15. kittycat01
    • one year ago
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    @Abhishek619 :/

  16. hartnn
    • one year ago
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    same thing....tan 2 thetha comes from tan (x+y) formula only

  17. Abhishek619
    • one year ago
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    |dw:1372850429715:dw|

  18. kittycat01
    • one year ago
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    oh :O

  19. kittycat01
    • one year ago
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    @Abhishek619 -oh :OO yeah we can do it in that way also :OOO tahnx :)

  20. hartnn
    • one year ago
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    with substitution, you would have got the same thing...

  21. kittycat01
    • one year ago
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    let me first @hartnn use ur method :D

  22. kittycat01
    • one year ago
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    @Abhishek619 @hartnn -answer is [2^(x+1)loge2]/(1+4^x) :'(

  23. hartnn
    • one year ago
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    i am never interested in final answer, just the method..... if your algebra part is correct, you WILL get correct final answer....

  24. kittycat01
    • one year ago
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    but the answer is in loge2 and having (1+4^x) also

  25. kittycat01
    • one year ago
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    well did he wrote 2tan^-12^x?????????

  26. kittycat01
    • one year ago
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    2tan^-1(2^x)

  27. hartnn
    • one year ago
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    ok, got till 2 tan inverse 2^x, right ? if you diff. that u get 2 * (1/1+(2^x)^2) 2^x ln 2 (ln = log_e) .... (2^x ln 2 comes from chain rule) yes...

  28. kittycat01
    • one year ago
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    oh x is in power :O

  29. kittycat01
    • one year ago
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    then m getting the answer :)

  30. hartnn
    • one year ago
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    yeah... (2^x)^2 = 4^x and 2.2^x = 2^(x+1) good!

  31. kittycat01
    • one year ago
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    @hartnn -thanx :) now i can do the rest ^_^

  32. hartnn
    • one year ago
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    welcome ^_^

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