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anonymous
 2 years ago
when u are having in this form then how to differentiate :)
tan^1(2^(x+1)/(14^x))
can i use substitution here ?
anonymous
 2 years ago
when u are having in this form then how to differentiate :) tan^1(2^(x+1)/(14^x)) can i use substitution here ?

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i don't think so substitution will work

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1do you know tan 2 theta formula ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0coz i have never did this type of question lol

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.12^(x+1) = 2. 2^x , 4^x = (2^x)^2 plug in 2^x = tan y and see the magic! (simplification :P)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0will it really works :PPPP lol i hate chain rule _

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0don't wanna use chain rule for inverse trig ...........

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1? what did you get after simplification ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1i don't think chain rule is required here...

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0use tan(x+y)=(tanx+tany)/(1tanxtany)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1same thing....tan 2 thetha comes from tan (x+y) formula only

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1372850429715:dw

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@Abhishek619 oh :OO yeah we can do it in that way also :OOO tahnx :)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1with substitution, you would have got the same thing...

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0let me first @hartnn use ur method :D

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@Abhishek619 @hartnn answer is [2^(x+1)loge2]/(1+4^x) :'(

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1i am never interested in final answer, just the method..... if your algebra part is correct, you WILL get correct final answer....

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0but the answer is in loge2 and having (1+4^x) also

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0well did he wrote 2tan^12^x?????????

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1ok, got till 2 tan inverse 2^x, right ? if you diff. that u get 2 * (1/1+(2^x)^2) 2^x ln 2 (ln = log_e) .... (2^x ln 2 comes from chain rule) yes...

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0then m getting the answer :)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1yeah... (2^x)^2 = 4^x and 2.2^x = 2^(x+1) good!

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@hartnn thanx :) now i can do the rest ^_^
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