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kittycat01

when u are having in this form then how to differentiate :) tan^-1(2^(x+1)/(1-4^x)) can i use substitution here ?

  • 9 months ago
  • 9 months ago

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  1. kittycat01
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    i don't think so substitution will work

    • 9 months ago
  2. hartnn
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    substitute 2^x = tan y

    • 9 months ago
  3. hartnn
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    lol, why not ?

    • 9 months ago
  4. hartnn
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    do you know tan 2 theta formula ?

    • 9 months ago
  5. kittycat01
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    coz i have never did this type of question lol

    • 9 months ago
  6. kittycat01
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    yep :)

    • 9 months ago
  7. kittycat01
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    2tanα/(1 – tan²α)

    • 9 months ago
  8. hartnn
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    2^(x+1) = 2. 2^x , 4^x = (2^x)^2 plug in 2^x = tan y and see the magic! (simplification :P)

    • 9 months ago
  9. kittycat01
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    will it really works :PPPP lol i hate chain rule -_-

    • 9 months ago
  10. kittycat01
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    don't wanna use chain rule for inverse trig ...........

    • 9 months ago
  11. hartnn
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    ? what did you get after simplification ?

    • 9 months ago
  12. hartnn
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    i don't think chain rule is required here...

    • 9 months ago
  13. kittycat01
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    wait :))

    • 9 months ago
  14. Abhishek619
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    use tan(x+y)=(tanx+tany)/(1-tanxtany)

    • 9 months ago
  15. kittycat01
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    @Abhishek619 :/

    • 9 months ago
  16. hartnn
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    same thing....tan 2 thetha comes from tan (x+y) formula only

    • 9 months ago
  17. Abhishek619
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    |dw:1372850429715:dw|

    • 9 months ago
  18. kittycat01
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    oh :O

    • 9 months ago
  19. kittycat01
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    @Abhishek619 -oh :OO yeah we can do it in that way also :OOO tahnx :)

    • 9 months ago
  20. hartnn
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    with substitution, you would have got the same thing...

    • 9 months ago
  21. kittycat01
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    let me first @hartnn use ur method :D

    • 9 months ago
  22. kittycat01
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    @Abhishek619 @hartnn -answer is [2^(x+1)loge2]/(1+4^x) :'(

    • 9 months ago
  23. hartnn
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    i am never interested in final answer, just the method..... if your algebra part is correct, you WILL get correct final answer....

    • 9 months ago
  24. kittycat01
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    but the answer is in loge2 and having (1+4^x) also

    • 9 months ago
  25. kittycat01
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    well did he wrote 2tan^-12^x?????????

    • 9 months ago
  26. kittycat01
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    2tan^-1(2^x)

    • 9 months ago
  27. hartnn
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    ok, got till 2 tan inverse 2^x, right ? if you diff. that u get 2 * (1/1+(2^x)^2) 2^x ln 2 (ln = log_e) .... (2^x ln 2 comes from chain rule) yes...

    • 9 months ago
  28. kittycat01
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    oh x is in power :O

    • 9 months ago
  29. kittycat01
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    then m getting the answer :)

    • 9 months ago
  30. hartnn
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    yeah... (2^x)^2 = 4^x and 2.2^x = 2^(x+1) good!

    • 9 months ago
  31. kittycat01
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    @hartnn -thanx :) now i can do the rest ^_^

    • 9 months ago
  32. hartnn
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    welcome ^_^

    • 9 months ago
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