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when u are having in this form then how to differentiate :)
tan^1(2^(x+1)/(14^x))
can i use substitution here ?
 9 months ago
 9 months ago
when u are having in this form then how to differentiate :) tan^1(2^(x+1)/(14^x)) can i use substitution here ?
 9 months ago
 9 months ago

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kittycat01Best ResponseYou've already chosen the best response.1
i don't think so substitution will work
 9 months ago

hartnnBest ResponseYou've already chosen the best response.1
do you know tan 2 theta formula ?
 9 months ago

kittycat01Best ResponseYou've already chosen the best response.1
coz i have never did this type of question lol
 9 months ago

hartnnBest ResponseYou've already chosen the best response.1
2^(x+1) = 2. 2^x , 4^x = (2^x)^2 plug in 2^x = tan y and see the magic! (simplification :P)
 9 months ago

kittycat01Best ResponseYou've already chosen the best response.1
will it really works :PPPP lol i hate chain rule _
 9 months ago

kittycat01Best ResponseYou've already chosen the best response.1
don't wanna use chain rule for inverse trig ...........
 9 months ago

hartnnBest ResponseYou've already chosen the best response.1
? what did you get after simplification ?
 9 months ago

hartnnBest ResponseYou've already chosen the best response.1
i don't think chain rule is required here...
 9 months ago

Abhishek619Best ResponseYou've already chosen the best response.1
use tan(x+y)=(tanx+tany)/(1tanxtany)
 9 months ago

hartnnBest ResponseYou've already chosen the best response.1
same thing....tan 2 thetha comes from tan (x+y) formula only
 9 months ago

Abhishek619Best ResponseYou've already chosen the best response.1
dw:1372850429715:dw
 9 months ago

kittycat01Best ResponseYou've already chosen the best response.1
@Abhishek619 oh :OO yeah we can do it in that way also :OOO tahnx :)
 9 months ago

hartnnBest ResponseYou've already chosen the best response.1
with substitution, you would have got the same thing...
 9 months ago

kittycat01Best ResponseYou've already chosen the best response.1
let me first @hartnn use ur method :D
 9 months ago

kittycat01Best ResponseYou've already chosen the best response.1
@Abhishek619 @hartnn answer is [2^(x+1)loge2]/(1+4^x) :'(
 9 months ago

hartnnBest ResponseYou've already chosen the best response.1
i am never interested in final answer, just the method..... if your algebra part is correct, you WILL get correct final answer....
 9 months ago

kittycat01Best ResponseYou've already chosen the best response.1
but the answer is in loge2 and having (1+4^x) also
 9 months ago

kittycat01Best ResponseYou've already chosen the best response.1
well did he wrote 2tan^12^x?????????
 9 months ago

hartnnBest ResponseYou've already chosen the best response.1
ok, got till 2 tan inverse 2^x, right ? if you diff. that u get 2 * (1/1+(2^x)^2) 2^x ln 2 (ln = log_e) .... (2^x ln 2 comes from chain rule) yes...
 9 months ago

kittycat01Best ResponseYou've already chosen the best response.1
oh x is in power :O
 9 months ago

kittycat01Best ResponseYou've already chosen the best response.1
then m getting the answer :)
 9 months ago

hartnnBest ResponseYou've already chosen the best response.1
yeah... (2^x)^2 = 4^x and 2.2^x = 2^(x+1) good!
 9 months ago

kittycat01Best ResponseYou've already chosen the best response.1
@hartnn thanx :) now i can do the rest ^_^
 9 months ago
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