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Tinascott

Write an equation for the line that is parallel to the given line and passes through the given point. y = x + 8; (2, 16)

  • 9 months ago
  • 9 months ago

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  1. Tinascott
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    y = x – 6 is this it?

    • 9 months ago
  2. souvik
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    any line that is parallel to y=x+8 has an equation y=x+ k where k is some constant and it passes through (2,16)..put these number in place of x and y

    • 9 months ago
  3. Tinascott
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    16=2+K or 16=10

    • 9 months ago
  4. souvik
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    16=2+k or k=14

    • 9 months ago
  5. souvik
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    so the equation is y=x+14

    • 9 months ago
  6. Tinascott
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    not one of my multible choices

    • 9 months ago
  7. dpasingh
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    Since the line is parallel to y = x + 8, equating it with y=mx+c we find slope m=1(since the coefficient of x is 1) Now line passes through point (2, 16) . Thus \[x_{1} =2, y _{1}=16\] Eq of line in slope point form is given as \[y-y _{1}=m(x-x _{1})\] I.e. y- 16=1(x-2) I.e. y- 16=x-2 I.e. y=x-2 + 16 I.e. y=x+14 Which is the required eq of the line

    • 9 months ago
  8. Tinascott
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    A. y = x B. y = x + 6 C. y = x – 6 D. y = x + 6 this is my choices

    • 9 months ago
  9. souvik
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    is the point is (2,16)?

    • 9 months ago
  10. souvik
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    B and D of your option is same..

    • 9 months ago
  11. Tinascott
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    that is what it is on my home work

    • 9 months ago
  12. Tinascott
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    is the point is (2,16)? yes that is what it says

    • 9 months ago
  13. souvik
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    hmm...

    • 9 months ago
  14. Tinascott
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    thanks for your help

    • 9 months ago
  15. souvik
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    welcome...

    • 9 months ago
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