## Tinascott 2 years ago Write an equation for the line that is parallel to the given line and passes through the given point. y = x + 8; (2, 16)

1. Tinascott

y = x – 6 is this it?

2. souvik

any line that is parallel to y=x+8 has an equation y=x+ k where k is some constant and it passes through (2,16)..put these number in place of x and y

3. Tinascott

16=2+K or 16=10

4. souvik

16=2+k or k=14

5. souvik

so the equation is y=x+14

6. Tinascott

not one of my multible choices

7. dpasingh

Since the line is parallel to y = x + 8, equating it with y=mx+c we find slope m=1(since the coefficient of x is 1) Now line passes through point (2, 16) . Thus \[x_{1} =2, y _{1}=16\] Eq of line in slope point form is given as \[y-y _{1}=m(x-x _{1})\] I.e. y- 16=1(x-2) I.e. y- 16=x-2 I.e. y=x-2 + 16 I.e. y=x+14 Which is the required eq of the line

8. Tinascott

A. y = x B. y = x + 6 C. y = x – 6 D. y = x + 6 this is my choices

9. souvik

is the point is (2,16)?

10. souvik

B and D of your option is same..

11. Tinascott

that is what it is on my home work

12. Tinascott

is the point is (2,16)? yes that is what it says

13. souvik

hmm...

14. Tinascott