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Tinascott

  • 2 years ago

Write an equation for the line that is parallel to the given line and passes through the given point. y = x + 8; (2, 16)

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  1. Tinascott
    • 2 years ago
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    y = x – 6 is this it?

  2. souvik
    • 2 years ago
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    any line that is parallel to y=x+8 has an equation y=x+ k where k is some constant and it passes through (2,16)..put these number in place of x and y

  3. Tinascott
    • 2 years ago
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    16=2+K or 16=10

  4. souvik
    • 2 years ago
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    16=2+k or k=14

  5. souvik
    • 2 years ago
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    so the equation is y=x+14

  6. Tinascott
    • 2 years ago
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    not one of my multible choices

  7. dpasingh
    • 2 years ago
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    Since the line is parallel to y = x + 8, equating it with y=mx+c we find slope m=1(since the coefficient of x is 1) Now line passes through point (2, 16) . Thus \[x_{1} =2, y _{1}=16\] Eq of line in slope point form is given as \[y-y _{1}=m(x-x _{1})\] I.e. y- 16=1(x-2) I.e. y- 16=x-2 I.e. y=x-2 + 16 I.e. y=x+14 Which is the required eq of the line

  8. Tinascott
    • 2 years ago
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    A. y = x B. y = x + 6 C. y = x – 6 D. y = x + 6 this is my choices

  9. souvik
    • 2 years ago
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    is the point is (2,16)?

  10. souvik
    • 2 years ago
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    B and D of your option is same..

  11. Tinascott
    • 2 years ago
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    that is what it is on my home work

  12. Tinascott
    • 2 years ago
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    is the point is (2,16)? yes that is what it says

  13. souvik
    • 2 years ago
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    hmm...

  14. Tinascott
    • 2 years ago
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    thanks for your help

  15. souvik
    • 2 years ago
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    welcome...

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