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xlegendx
 one year ago
LEGEN...waitforit...DARIDDLE:
How many people should be in a room so that there is a 99% probability that two or more people share the same birthday?
Hint: whoever gets it right with solutions gets a medal
xlegendx
 one year ago
LEGEN...waitforit...DARIDDLE: How many people should be in a room so that there is a 99% probability that two or more people share the same birthday? Hint: whoever gets it right with solutions gets a medal

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hartnn
 one year ago
Best ResponseYou've already chosen the best response.1the dreaded riddles are back!

xlegendx
 one year ago
Best ResponseYou've already chosen the best response.0these ones are legendary. i don't make puny riddles like the original

xlegendx
 one year ago
Best ResponseYou've already chosen the best response.0so @hartnn do you know the answer?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1haven't tried yet...i would always prefer helping than satisfying my own thirst of solving puzzles...i'll try that in free time :)

xlegendx
 one year ago
Best ResponseYou've already chosen the best response.0helping huh. haven't tried that in a while

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1i try these problems by taking small numbers first let there be just 2 people in that room then the probability "that two or more people share the same birthday" will be 1 probability that BOTH will not have same birthday (assuming 366 days a year) so, \(\large 1 \dfrac{366}{366}\times \dfrac{365}{366}\) now extending this for 'n' people \(\large 0.99 =1 \dfrac{\dfrac{366!}{(366n)!}}{366^n}\) am i on right path ? (wondering how the hell can i solve that for n :O O.o)

xlegendx
 one year ago
Best ResponseYou've already chosen the best response.0lol. am not saying if you're on the right path or not. just tell me the answer and i'll tell you if it's right. that's how riddles work

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1rounding to nearest integer i am getting 55 people (infact 55 or more!)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1i had my chance, i'll let others try....
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