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xlegendx
Group Title
LEGEN...waitforit...DARIDDLE:
How many people should be in a room so that there is a 99% probability that two or more people share the same birthday?
Hint: whoever gets it right with solutions gets a medal
 one year ago
 one year ago
xlegendx Group Title
LEGEN...waitforit...DARIDDLE: How many people should be in a room so that there is a 99% probability that two or more people share the same birthday? Hint: whoever gets it right with solutions gets a medal
 one year ago
 one year ago

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hartnn Group TitleBest ResponseYou've already chosen the best response.1
the dreaded riddles are back!
 one year ago

xlegendx Group TitleBest ResponseYou've already chosen the best response.0
these ones are legendary. i don't make puny riddles like the original
 one year ago

xlegendx Group TitleBest ResponseYou've already chosen the best response.0
so @hartnn do you know the answer?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
haven't tried yet...i would always prefer helping than satisfying my own thirst of solving puzzles...i'll try that in free time :)
 one year ago

xlegendx Group TitleBest ResponseYou've already chosen the best response.0
helping huh. haven't tried that in a while
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i try these problems by taking small numbers first let there be just 2 people in that room then the probability "that two or more people share the same birthday" will be 1 probability that BOTH will not have same birthday (assuming 366 days a year) so, \(\large 1 \dfrac{366}{366}\times \dfrac{365}{366}\) now extending this for 'n' people \(\large 0.99 =1 \dfrac{\dfrac{366!}{(366n)!}}{366^n}\) am i on right path ? (wondering how the hell can i solve that for n :O O.o)
 one year ago

xlegendx Group TitleBest ResponseYou've already chosen the best response.0
lol. am not saying if you're on the right path or not. just tell me the answer and i'll tell you if it's right. that's how riddles work
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
rounding to nearest integer i am getting 55 people (infact 55 or more!)
 one year ago

xlegendx Group TitleBest ResponseYou've already chosen the best response.0
ooooh so close
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i had my chance, i'll let others try....
 one year ago
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