Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

xlegendx

  • 2 years ago

LEGEN...waitforit...DARIDDLE: How many people should be in a room so that there is a 99% probability that two or more people share the same birthday? Hint: whoever gets it right with solutions gets a medal

  • This Question is Closed
  1. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the dreaded riddles are back!

  2. xlegendx
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    these ones are legendary. i don't make puny riddles like the original

  3. xlegendx
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so @hartnn do you know the answer?

  4. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    haven't tried yet...i would always prefer helping than satisfying my own thirst of solving puzzles...i'll try that in free time :)

  5. xlegendx
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    helping huh. haven't tried that in a while

  6. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i try these problems by taking small numbers first let there be just 2 people in that room then the probability "that two or more people share the same birthday" will be 1- probability that BOTH will not have same birthday (assuming 366 days a year) so, \(\large 1- \dfrac{366}{366}\times \dfrac{365}{366}\) now extending this for 'n' people \(\large 0.99 =1- \dfrac{\dfrac{366!}{(366-n)!}}{366^n}\) am i on right path ? (wondering how the hell can i solve that for n :O O.o)

  7. xlegendx
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lol. am not saying if you're on the right path or not. just tell me the answer and i'll tell you if it's right. that's how riddles work

  8. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    rounding to nearest integer i am getting 55 people (infact 55 or more!)

  9. xlegendx
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ooooh so close

  10. xlegendx
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but no

  11. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i had my chance, i'll let others try....

  12. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.