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anonymous
 3 years ago
Solve by completing the square: x28x+7=0
That is an x squared.
Thanks.
anonymous
 3 years ago
Solve by completing the square: x28x+7=0 That is an x squared. Thanks.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Let's use \(x^2  4x  8 = 0\) to demonstrate Completing the Square. 1. Put the constant term on the other side of the equation by adding 8 to both sides. \(x^2  4x = 8\) 2. Look at the coefficient of the xterm (4) > take half this term (2) and square it (+4). Add this to both sides. \(x^2  4x + 4 = 12\) This is a perfect square and can be factored. 3. Factor: \((x2)^2\) (hint: The constant term is the same as half of the x term that was squared in step 2.) 4. Solve for x: \(\sqrt{(x2)^2} = \sqrt{12}\) \(x  2 = \pm 2 \sqrt{3}\) \(x = 2 \pm 2 \sqrt{3}\) Please ask if anything is unclear.
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