Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Lees0002

  • 2 years ago

Solve by completing the square: x2-8x+7=0 That is an x squared. Thanks.

  • This Question is Open
  1. gypsy1274
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Let's use \(x^2 - 4x - 8 = 0\) to demonstrate Completing the Square. 1. Put the constant term on the other side of the equation by adding 8 to both sides. \(x^2 - 4x = 8\) 2. Look at the coefficient of the x-term (-4) -> take half this term (-2) and square it (+4). Add this to both sides. \(x^2 - 4x + 4 = 12\) This is a perfect square and can be factored. 3. Factor: \((x-2)^2\) (hint: The constant term is the same as half of the x term that was squared in step 2.) 4. Solve for x: \(\sqrt{(x-2)^2} = \sqrt{12}\) \(x - 2 = \pm 2 \sqrt{3}\) \(x = 2 \pm 2 \sqrt{3}\) Please ask if anything is unclear.

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy