anonymous
  • anonymous
Solve by completing the square: x2-8x+7=0 That is an x squared. Thanks.
HippoCampus Algebra & Geometry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Let's use \(x^2 - 4x - 8 = 0\) to demonstrate Completing the Square. 1. Put the constant term on the other side of the equation by adding 8 to both sides. \(x^2 - 4x = 8\) 2. Look at the coefficient of the x-term (-4) -> take half this term (-2) and square it (+4). Add this to both sides. \(x^2 - 4x + 4 = 12\) This is a perfect square and can be factored. 3. Factor: \((x-2)^2\) (hint: The constant term is the same as half of the x term that was squared in step 2.) 4. Solve for x: \(\sqrt{(x-2)^2} = \sqrt{12}\) \(x - 2 = \pm 2 \sqrt{3}\) \(x = 2 \pm 2 \sqrt{3}\) Please ask if anything is unclear.

Looking for something else?

Not the answer you are looking for? Search for more explanations.