Let's use $$x^2 - 4x - 8 = 0$$ to demonstrate Completing the Square. 1. Put the constant term on the other side of the equation by adding 8 to both sides. $$x^2 - 4x = 8$$ 2. Look at the coefficient of the x-term (-4) -> take half this term (-2) and square it (+4). Add this to both sides. $$x^2 - 4x + 4 = 12$$ This is a perfect square and can be factored. 3. Factor: $$(x-2)^2$$ (hint: The constant term is the same as half of the x term that was squared in step 2.) 4. Solve for x: $$\sqrt{(x-2)^2} = \sqrt{12}$$ $$x - 2 = \pm 2 \sqrt{3}$$ $$x = 2 \pm 2 \sqrt{3}$$ Please ask if anything is unclear.