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Summersnow8
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Male mosquitoes in the mood for mating find female mosquitoes of their own species by listening for the characteristic "buzzing" frequency of the female's wing beats. This frequency is about 620 wing beats per second.
How many cycles of oscillation does the radiation from a cesium133 atom complete during one mosquito wing beat?
I know cesium133 atom is 9,192,631,770 cycles/ second
 one year ago
 one year ago
Summersnow8 Group Title
Male mosquitoes in the mood for mating find female mosquitoes of their own species by listening for the characteristic "buzzing" frequency of the female's wing beats. This frequency is about 620 wing beats per second. How many cycles of oscillation does the radiation from a cesium133 atom complete during one mosquito wing beat? I know cesium133 atom is 9,192,631,770 cycles/ second
 one year ago
 one year ago

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whpalmer4 Group TitleBest ResponseYou've already chosen the best response.2
620 wing beats = 1 sec 9,192,631,770 cycles = 1 sec 9,192,631,770 cycles = 620 wing beats divide both by 620 wing beats 9192631770/620 cycles / wing beat
 one year ago

Summersnow8 Group TitleBest ResponseYou've already chosen the best response.0
i tried that but it said it was wrong
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.2
what did you get for the answer?
 one year ago

Summersnow8 Group TitleBest ResponseYou've already chosen the best response.0
25535088.25
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.2
well, that IS wrong :) try doing it again.
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.2
9192631770/620 =
 one year ago

Summersnow8 Group TitleBest ResponseYou've already chosen the best response.0
1414251.042
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.2
no, that's not right either. have you pressed the clear or all clear button on your calculator before starting the problem?
 one year ago

Summersnow8 Group TitleBest ResponseYou've already chosen the best response.0
gahhhh
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.2
correct answer should be 1.48268 * 10^7, or digits to that effect...
 one year ago

Summersnow8 Group TitleBest ResponseYou've already chosen the best response.0
14142510.42
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.2
you aren't entering the same numbers as I am.
 one year ago

Summersnow8 Group TitleBest ResponseYou've already chosen the best response.0
okay what are you entering
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.2
9 1 9 2 6 3 1 7 7 0 / 6 2 0 =
 one year ago

Summersnow8 Group TitleBest ResponseYou've already chosen the best response.0
bahahaha, okay, i was doing 650, damn thing... so do sif figs count? 1.4 x 10 ^7
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.2
I can't really advise you on whether or not they want you to round to an appropriate number of significant figures. If doing it on paper, I would write something like "\(1.48268 * 10^7\) cycles which is \(1.5 *10^7\) cycles to 2 significant figures" [note that it is 1.48... so rounds to 1.5, not 1.4]
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.2
because the problem says "about 620 beats per second" perhaps we should go with the two significant figures suggested by "620".
 one year ago

Summersnow8 Group TitleBest ResponseYou've already chosen the best response.0
okay thanks :) lifesaver
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.2
you're welcome!
 one year ago
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