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Male mosquitoes in the mood for mating find female mosquitoes of their own species by listening for the characteristic "buzzing" frequency of the female's wing beats. This frequency is about 620 wing beats per second. How many cycles of oscillation does the radiation from a cesium-133 atom complete during one mosquito wing beat? I know cesium-133 atom is 9,192,631,770 cycles/ second

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620 wing beats = 1 sec 9,192,631,770 cycles = 1 sec 9,192,631,770 cycles = 620 wing beats divide both by 620 wing beats 9192631770/620 cycles / wing beat
i tried that but it said it was wrong
what did you get for the answer?

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Other answers:

well, that IS wrong :-) try doing it again.
9192631770/620 =
no, that's not right either. have you pressed the clear or all clear button on your calculator before starting the problem?
correct answer should be 1.48268 * 10^7, or digits to that effect...
you aren't entering the same numbers as I am.
okay what are you entering
9 1 9 2 6 3 1 7 7 0 / 6 2 0 =
bahahaha, okay, i was doing 650, damn thing... so do sif figs count? 1.4 x 10 ^7
I can't really advise you on whether or not they want you to round to an appropriate number of significant figures. If doing it on paper, I would write something like "\(1.48268 * 10^7\) cycles which is \(1.5 *10^7\) cycles to 2 significant figures" [note that it is 1.48... so rounds to 1.5, not 1.4]
because the problem says "about 620 beats per second" perhaps we should go with the two significant figures suggested by "620".
okay thanks :) lifesaver
you're welcome!

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