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Summersnow8

Male mosquitoes in the mood for mating find female mosquitoes of their own species by listening for the characteristic "buzzing" frequency of the female's wing beats. This frequency is about 620 wing beats per second. How many cycles of oscillation does the radiation from a cesium-133 atom complete during one mosquito wing beat? I know cesium-133 atom is 9,192,631,770 cycles/ second

  • 9 months ago
  • 9 months ago

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  1. whpalmer4
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    620 wing beats = 1 sec 9,192,631,770 cycles = 1 sec 9,192,631,770 cycles = 620 wing beats divide both by 620 wing beats 9192631770/620 cycles / wing beat

    • 9 months ago
  2. Summersnow8
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    i tried that but it said it was wrong

    • 9 months ago
  3. whpalmer4
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    what did you get for the answer?

    • 9 months ago
  4. Summersnow8
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    25535088.25

    • 9 months ago
  5. whpalmer4
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    well, that IS wrong :-) try doing it again.

    • 9 months ago
  6. whpalmer4
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    9192631770/620 =

    • 9 months ago
  7. Summersnow8
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    1414251.042

    • 9 months ago
  8. whpalmer4
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    no, that's not right either. have you pressed the clear or all clear button on your calculator before starting the problem?

    • 9 months ago
  9. Summersnow8
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    gahhhh

    • 9 months ago
  10. whpalmer4
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    correct answer should be 1.48268 * 10^7, or digits to that effect...

    • 9 months ago
  11. Summersnow8
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    14142510.42

    • 9 months ago
  12. whpalmer4
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    you aren't entering the same numbers as I am.

    • 9 months ago
  13. Summersnow8
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    okay what are you entering

    • 9 months ago
  14. whpalmer4
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    9 1 9 2 6 3 1 7 7 0 / 6 2 0 =

    • 9 months ago
  15. Summersnow8
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    bahahaha, okay, i was doing 650, damn thing... so do sif figs count? 1.4 x 10 ^7

    • 9 months ago
  16. Summersnow8
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    sig*

    • 9 months ago
  17. whpalmer4
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    I can't really advise you on whether or not they want you to round to an appropriate number of significant figures. If doing it on paper, I would write something like "\(1.48268 * 10^7\) cycles which is \(1.5 *10^7\) cycles to 2 significant figures" [note that it is 1.48... so rounds to 1.5, not 1.4]

    • 9 months ago
  18. whpalmer4
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    because the problem says "about 620 beats per second" perhaps we should go with the two significant figures suggested by "620".

    • 9 months ago
  19. Summersnow8
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    okay thanks :) lifesaver

    • 9 months ago
  20. whpalmer4
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    you're welcome!

    • 9 months ago
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