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Summersnow8 Group Title

Male mosquitoes in the mood for mating find female mosquitoes of their own species by listening for the characteristic "buzzing" frequency of the female's wing beats. This frequency is about 620 wing beats per second. How many cycles of oscillation does the radiation from a cesium-133 atom complete during one mosquito wing beat? I know cesium-133 atom is 9,192,631,770 cycles/ second

  • one year ago
  • one year ago

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  1. whpalmer4 Group Title
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    620 wing beats = 1 sec 9,192,631,770 cycles = 1 sec 9,192,631,770 cycles = 620 wing beats divide both by 620 wing beats 9192631770/620 cycles / wing beat

    • one year ago
  2. Summersnow8 Group Title
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    i tried that but it said it was wrong

    • one year ago
  3. whpalmer4 Group Title
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    what did you get for the answer?

    • one year ago
  4. Summersnow8 Group Title
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    25535088.25

    • one year ago
  5. whpalmer4 Group Title
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    well, that IS wrong :-) try doing it again.

    • one year ago
  6. whpalmer4 Group Title
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    9192631770/620 =

    • one year ago
  7. Summersnow8 Group Title
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    1414251.042

    • one year ago
  8. whpalmer4 Group Title
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    no, that's not right either. have you pressed the clear or all clear button on your calculator before starting the problem?

    • one year ago
  9. Summersnow8 Group Title
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    gahhhh

    • one year ago
  10. whpalmer4 Group Title
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    correct answer should be 1.48268 * 10^7, or digits to that effect...

    • one year ago
  11. Summersnow8 Group Title
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    14142510.42

    • one year ago
  12. whpalmer4 Group Title
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    you aren't entering the same numbers as I am.

    • one year ago
  13. Summersnow8 Group Title
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    okay what are you entering

    • one year ago
  14. whpalmer4 Group Title
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    9 1 9 2 6 3 1 7 7 0 / 6 2 0 =

    • one year ago
  15. Summersnow8 Group Title
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    bahahaha, okay, i was doing 650, damn thing... so do sif figs count? 1.4 x 10 ^7

    • one year ago
  16. Summersnow8 Group Title
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    sig*

    • one year ago
  17. whpalmer4 Group Title
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    I can't really advise you on whether or not they want you to round to an appropriate number of significant figures. If doing it on paper, I would write something like "\(1.48268 * 10^7\) cycles which is \(1.5 *10^7\) cycles to 2 significant figures" [note that it is 1.48... so rounds to 1.5, not 1.4]

    • one year ago
  18. whpalmer4 Group Title
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    because the problem says "about 620 beats per second" perhaps we should go with the two significant figures suggested by "620".

    • one year ago
  19. Summersnow8 Group Title
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    okay thanks :) lifesaver

    • one year ago
  20. whpalmer4 Group Title
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    you're welcome!

    • one year ago
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