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 one year ago
Male mosquitoes in the mood for mating find female mosquitoes of their own species by listening for the characteristic "buzzing" frequency of the female's wing beats. This frequency is about 620 wing beats per second.
How many cycles of oscillation does the radiation from a cesium133 atom complete during one mosquito wing beat?
I know cesium133 atom is 9,192,631,770 cycles/ second
 one year ago
Male mosquitoes in the mood for mating find female mosquitoes of their own species by listening for the characteristic "buzzing" frequency of the female's wing beats. This frequency is about 620 wing beats per second. How many cycles of oscillation does the radiation from a cesium133 atom complete during one mosquito wing beat? I know cesium133 atom is 9,192,631,770 cycles/ second

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whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2620 wing beats = 1 sec 9,192,631,770 cycles = 1 sec 9,192,631,770 cycles = 620 wing beats divide both by 620 wing beats 9192631770/620 cycles / wing beat

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0i tried that but it said it was wrong

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2what did you get for the answer?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2well, that IS wrong :) try doing it again.

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2no, that's not right either. have you pressed the clear or all clear button on your calculator before starting the problem?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2correct answer should be 1.48268 * 10^7, or digits to that effect...

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2you aren't entering the same numbers as I am.

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0okay what are you entering

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.29 1 9 2 6 3 1 7 7 0 / 6 2 0 =

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0bahahaha, okay, i was doing 650, damn thing... so do sif figs count? 1.4 x 10 ^7

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2I can't really advise you on whether or not they want you to round to an appropriate number of significant figures. If doing it on paper, I would write something like "\(1.48268 * 10^7\) cycles which is \(1.5 *10^7\) cycles to 2 significant figures" [note that it is 1.48... so rounds to 1.5, not 1.4]

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2because the problem says "about 620 beats per second" perhaps we should go with the two significant figures suggested by "620".

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.0okay thanks :) lifesaver
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